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irina [24]
3 years ago
6

2x-3(x-4y)+1/2(8x-12y)

Mathematics
1 answer:
Evgen [1.6K]3 years ago
5 0
1st step:
Multiply 2x-3 with (x-4y), then Multiply 1/2 with (8x-12y)
= 2x^2-8xy-3x+4x-6y
2nd step:
Add the common variables
=2x^2-8xy+x-6y

The standard form will be 2x^2-8xy+x-6y.
The factor form I don't know sorry.
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