Answer:
D)$732.84
Step-by-step explanation:
A=p(1+r/n)^nt
P=principal=$600
r=5%=0.05
t=4 years
n=12 months
A=p(1+r/n)^nt
=600(1+0.05/12)^12*4
=600(1+0.0041666666666 )^48
=600(1.0041666666666 )^48
=600( 1.2208953550215 )
=732.53
A=$732.53
Option D)$732.84 is the answer
Let X represent a random variable representing the birth weights of babies, and let x be the required cut-off, then
P(X < x) = 0.02
P(z < (x - 3419)/494) = 0.02
1 - P(z < (3419 - x)/494) = 0.02
P(z < (3419 - x)/494) = 1 - 0.02 = 0.98
(3419 - x)/469 = 2.04
3419 - x = 956.76
x = 3419 - 956.76 = 2462.24
Therefore, the weight to be used as cut-off is 2462.24 g
Answer:
4^n-1
Step-by-step explanation:
So given sequence is a geometric sequence where terms increase or decrease by a constant common ratio(r)
Formula to find terms in Geometric sequence is " ar^n-1 where a is first term , r is common ratio and n is number of items
In this case , first term (a) is 1 , common ratio(r) is succeeding term/preceding term = 4/1 = 4 and number of items be (n).
Applying "ar^n-1 " we get,
1*4^n-1 which is , 4^n-1
Thats the formula which represents the situation....
Well, we should first decide on our variables. Let's replace "thumb drives" with the letter "t", and "compact disk" with the letter "c".
Now, to understand the sentence. "5 thumb drives have 9 gigabytes more capacity than 1 compact disk." So, what does that mean? Well, if a compact disk has 10 gigabytes of capacity, then I suppose 5 thumb drives would have 19 gigabytes of capacity all together. So, we're just adding +9.
Alright, so as a linear equation:
"5 thumb drives have 9 gigabytes more capacity than 1 compact disk"
5t = c + 9