Answer:
225 ft^2
Step-by-step explanation:
From what we have in the question, we have 60 ft of fencing
To maximize the area, we will need to have a square
For a square, the length of all sides are equal
Let us call one of the sides s
Thus, from the perimeter of the square;
4s = 60
s = 60/4
s = 15 ft
The area is thus, the product of the side length of the square
15 * 15 = 225 ft^2
Answer:
first you have to find the values of the two sides of the rectangle. BC=5 cm
Area of a trapezium
= 1/2 x (5+9) x (11-5)
= 42 cm^2
Answer:
3.75 or 3 3/4
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
The law of cosines is a² = b²+c²-2bc(cos A).
We will use s in place of a, since it is the unknown side. This makes b and c 8 and 9.
Angle A will be the angle opposite side a, or in this case side s. This makes it 111.
This gives us
s² = 8²+9²-2(8)(9)(cos 111)
s² = 64+81-2(8)(9)(cos 111)
s² = 145-144(cos 111)
s² = 196.605
Take the square root of each side:
√(s²) = √(196.605)
s = 14.02 ≈ 14
You can use the distibutive property by breaking apart the bigger number (38) into 30 and 8. Now, you can do: (9 x 30) + (9 x 8)
I hope this helps!!!
:D
