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Finger [1]
3 years ago
12

Pleaseeeee heeeelp write a polynomial function of least degree with the given zero. -1+ √ 2, √ 3

Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0

A polynomial p(x) has a root x_0 if it is a multiple of (x-x_0)

So, if you want roots -1, \sqrt{2}, \sqrt{3}, your polynomial must be a multiple of

(x+1)\left(x-\sqrt{2}\right)\left(x-\sqrt{3}\right)

If we add another monomial, we would raise the degree, but we want it to be as low as possible. So, we can only add a multiplicative constant: your polynomial is

p(x)=a(x+1)\left(x-\sqrt{2}\right)\left(x-\sqrt{3}\right)

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3 years ago
Write the equation of the line that goes through each set of points------ (-1.6),(3-,2)
Maksim231197 [3]

Answer:

The equation that goes through this set of points is y = -x + 5

Step-by-step explanation:

In order to find this, we need to start by finding the slope. For that we use the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (6 - -2)/(-1 - 3)

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m = -1

Now that we have this, we can use the slope and a point in point-slope form to get the equation.

y - y1 = m(x - x1)

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y - 6 = -1(x + 1)

y - 6 = -x - 1

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3 years ago
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Luda [366]
8 x2 is 16; we have a negative sign, so that makes our answer -16
4 0
3 years ago
Read 2 more answers
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