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Minchanka [31]
3 years ago
7

What's the answer to this​

Mathematics
1 answer:
larisa86 [58]3 years ago
4 0
The answer is, y=-1x+9
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Y = a x 3 + b x 2 + c x + d
Alla [95]

Answer:

If its a cube function. Then I think this is the answer. Can you mark brainliest? And can you tell me if it's right or wrong?

Step-by-step explanation:

Consider the cubic function f(x) = ax^3 + bx^2 + cx + d. Determine the values of the constants a, b, c and d so that f(x) has a point of inflection at the origin and a local maximum at the point (2,...

Consider the cubic function f(x) = ax^3 + bx^2 + cx + d. Determine the values of the constants a, b, c and d

so that f(x) has a point of inflection at the origin and a local maximum at the point (2, 4). ==>c=3

8 0
3 years ago
Which of the following numbers has the commas in the correct positions
Genrish500 [490]
BBB because it has commas after the right units
6 0
3 years ago
3. A fence is made up of eight 8 5/7-foot sections. How long is the fence? Write your answer as a mixed number in lowest terms.
rewona [7]

Answer:

Step-by-step explanation:

3)A fence is made up of eight 8 5/7-foot sections. This means the total number of feet's is 8 × 8 5/7. Expressing 8 5/7 as improper fraction, it will be 61/7 feet's

The total length of the fence =

8 × 61/7 = 488/7 feet's

Expressing as mixed fraction, it becomes

69 5/7 feets

4) Cynthia spent 3/4 of her time at the gym on the stair machine. She spent a total of 21 3/4 minutes on the stair machine. This means that the time she spent on the gym is 3/4 × 21 3/4 .

Converting 21 3/4 to improper fraction, it becomes 87/4

The time she spent on the gym

= 3/4 × 87/4 = 261/16

= 16 5/16 minutes

5) On Monday, Ryan jogged 1 ½ miles in ¼ hour. On Wednesday he jogged 2 1/3 miles in 1/3 hour. Converting to improper fractions,

the miles ran on Monday= 1 ½ miles = 3/2 miles

the miles jogged on wednesday = 2 1/3 miles = 7/3 miles

How much farther did Ryan jog on Wednesday than on Monday? This would be 7/3 - 3/2

= 5/6 miles

6) One requires 2/3 cup of flour, another requires 7/8 cup of flour, and the third require 3/4 cup of flour.

Total amount of flour that Josh will use is

2/3 +7/8 +3/4 = (16+21+18)/24

= 55/25 = 2 7/25 cups of flour

5 0
3 years ago
Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm
Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 6, \sigma = 0.2

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

Z = 0

Z = 0 has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 5.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

Z = -5

Z = -5 has a pvalue of 0.

1 - 0 = 1

5 0
3 years ago
If f(x) =2x²-x, find f(-4)-f(9)​
sergeinik [125]
F(-4) = 36
f(9) = 153
3 0
3 years ago
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