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m_a_m_a [10]
2 years ago
15

Write the quadratic equation in standard form please -5x^2-6x=-1+2x

Mathematics
1 answer:
slava [35]2 years ago
8 0

Answer:

-5x^2-8x+1=0

Hope this helps!!

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You flipped a coin 50 times and got 23 heads.What is the experimental probability of getting a head? Write your answer as a frac
lys-0071 [83]

Answer:

23/50, 0.46, and 46%

Step-by-step explanation:


This problem is stating that every fifty times you flip a coin you get 23 heads. Finding the fraction is simple, it would be 23/50 because it is expressing the probability. The problem clearly states that every 50 times you get 23 heads. To find the decimal, take the fraction, 23/50, and multiply the numerator and denominator by 2. you get 46/100 which is 0.46. A percent is just a fraction out of a 100 which would make the percent 46.


8 0
2 years ago
Work out the value of 23 - 4b. When b = 3
Serggg [28]

Answer:

11

Step-by-step explanation:

Substitute 3 for b

23 - 4(3)

Multiply 4(3) = 12

23 - 12

Subtract

23 - 12 = 11

8 0
3 years ago
Read 2 more answers
In ABC,if sin A=4/5 and tan A =4/3,then what is cow A?
nlexa [21]

I hope this helps you

5 0
3 years ago
Read 2 more answers
Manish and Jhanavi each receive an equal bonus. Manish has 1/2 fraction of allowance as saving accounts , 1/4 of the fraction he
Valentin [98]

Answer:

Manish has Rs630 while Jhanavi has Rs168.

Step-by-step explanation:

The fraction Manish would have left would be subtracting the fraction on savings as well as that spent on the mall. Which would be;

1 -( 1/2 + 1/4)=1 -3/4 = 1/4

Meaning Manish had 1/4 of his allowance left on him.

Which means 1/4 × Rs. 2520=Rs630

Similarly for Jhanavi, we have :

The fraction left as

1-(1/3 +3/5) = 1 - ( 14/15) = 1/15

Meaning 1/15 of the allowance got remains which is;

1/15 × Rs. 2520= Rs.168

3 0
3 years ago
(-11r+14+9r^3) + (3-8r^5+14r^3)
murzikaleks [220]
-8r^5+23r^3-11r+17

Wasn’t Sure What It Was Asking So Hopefully That Works For You
3 0
3 years ago
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