Question

Find the value of x in the triangle shown below.

Answer 1

x=4 because it makes up a square and all sides are the same length on a square

Answer 2

Answer:

b = $2\sqrt{5}$ = 4.47

Step-by-step explanation:

The Pythagorean Theorem is $a^{2}+b^{2} = c^{2}$

Let's say a= 2, b= x, and c = 4

Since we need to find the value of x, we will rearrange our equation

$a^{2} + c^{2} = b^{2}$

Now, we substitute plug in the numbers for the values

$(2)^{2} + (4)^{2} = b^{2}$

Then, find $(2)^{2}$ and $(4)^{2}$

$(2)^{2} = 4$

$(4)^{2} = 16$

4 + 16 = $b^{2}$

Add 4 and 16

4 + 16 = 20

20 = $b^{2}$

We still need to find what b is by itself, we need to get rid of the exponent.

So, we need to take the square root of both sides.

$\sqrt{20} = \sqrt{b}$

$\sqrt{20} = 2\sqrt{5}$

b = $2\sqrt{5}$ = 4.47

And that would be your answer