If h(x) = x – 7 and g(x) = x2, which expression is equivalent to mc022-1.jpg?
2 answers:
<span>the answer:
the full question is as follow:
If h(x) = x – 7 and g(x) = x2, which expression is equivalent to (g*h)(5)?
A (5 – 7)2,
B (5)2 – 7,
C (5)2(5 – 7),
D (5 – 7)x2
first, the main rule of the product between two functions g and h is
g(x)*h(x)= (g*h)(x)
</span>h(x) = x – 7 and g(x)=x², so (g*h)(x)= g(x)*h(x)=[x²][x – 7 ]= x^3 -7x²
(g*h)(x)= x^3 -7x², therefore, (g*h)(5)= 5^3 -7*5² = -50 = (5)2(5 – 7)
finally, the answer is C (5)2(5 – 7),
Answer:
A. (5-7)2
Step-by-step explanation:
I took an educational guess on edgen. and got this right.
You might be interested in
Answer: 25,600
explanation: subtracting the bigger number to the lowest number.
If 3 is the bold number then the answer is D. <span>#TeamAlvaxic</span>
Yes in order for them to be symmetrical they both have to be Symmetrical or the same
8 = 2^3
27 = 3^3
(2^3)*(3^3)=6^3
Cube root of 6^3 = 6