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motikmotik
3 years ago
11

If h(x) = x – 7 and g(x) = x2, which expression is equivalent to mc022-1.jpg?

Mathematics
2 answers:
damaskus [11]3 years ago
8 0
<span>the answer:
the full question is as follow:

If h(x) = x – 7 and g(x) = x2, which expression is equivalent to (g*h)(5)?

A (5 – 7)2,
B (5)2 – 7,
C (5)2(5 – 7),
D (5 – 7)x2

first, the main rule of the product between two functions g and h is

g(x)*h(x)= (g*h)(x)

</span>h(x) = x – 7 and g(x)=x², so (g*h)(x)= g(x)*h(x)=[x²][x – 7 ]= x^3 -7x²

(g*h)(x)= x^3 -7x², therefore, (g*h)(5)= 5^3 -7*5² = -50 = (5)2(5 – 7)

finally, the answer is C (5)2(5 – 7), 
Yuri [45]3 years ago
5 0

Answer:

A. (5-7)2

Step-by-step explanation:

I took an educational guess on edgen. and got this right.

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3 years ago
8,264 is divisible by 3? True or false?
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7 0
4 years ago
Read 2 more answers
Sara plotted the locations of the trees in a park on a coordinate grid. She plotted an oak tree which was in the middle of the p
padilas [110]

Answer: 10.2\ yards

Step-by-step explanation:

<h3> "Sara plotted the locations of the trees in a park on a coordinate grid. She plotted an oak tree, which was in the middle of the park, at the origin. She plotted a maple tree, which was 10 yards away from the oak tree, at the point (10,0) . Then she plotted a pine tree at the point (-2.4, 5) and an apple tree at the point (7.8, 5) What is the distance, in yards, between the pine tree and the apple tree in the</h3><h3>park?"</h3>

For this exercise you need to use the following formula, which can be used for calculate the distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

In this case, you need to find distance, in yards, between the pine tree and the apple tree in the park.

You know that pine tree is located at the point (-2.4, 5) and the apple tree is located at the point (7.8, 5).

So, you can say that:

x_2=-2.4\\x_1=7.8\\\\y_2=5\\y_1=5

Knowing these values, you can substitute them into the formula and then evaluate, in order to find the distance, in yards, between the pine tree and the apple tree in the park.

This is:

d=\sqrt{(-2.4-7.8)^2+(5-5)^2}=10.2\ yards

8 0
3 years ago
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Elenna [48]
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Used:\\\\\log_aa=1\\\\\log_ab^n=n\log_ab\\\\\log_ab=\dfrac{\log_cb}{\log_ca}
3 0
3 years ago
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Answer:

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Step-by-step explanation:

The internal validity here is weak

Internal validity describes the extent to which an evidence weighs the cause and effect claim. In this study, the internal validity that brought about failure in the new exam is mainly due to the environment where the exam was written and not the new exam itself.

So this validity is weak in claiming that the new exam is not a good substitute for the old exam.

Putting them in the same good environment might help the researchers to draw a better conclusion.

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