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3 years ago

If 2 gallons of paint is $19.20, 1 quart is?

Mathematics

2 answers:

lianna [129]3 years ago

6 0

Answer:

$2.40

Step-by-step explanation:

2 gallons = $19.20

1 quart = ?

Convert quart to gallons.

1 quart = 0.25 gallons

2 gallons = $19.20

0.25 gallons = x

Cross multiply.

19.20 × 0.25 = 2x

4.8 = 2x

x = 2.4

shutvik [7]3 years ago

3 0

Answer:

1 gallon is 4 quarts

2 gallons are 8 quarts

19.20 (cost) / 8 quarts = $2.40 for 1 quart

2.40 is the answer

Hope this helps

Step-by-step explanation:

You might be interested in

If it takes 4 men 6hours to repair a road, how long will it take 7 men to do the job if they work at the same rate.

Crank

Tricky question. This isn't a ratio question even though it seems like one.

First divide 7 by 4.
$7 \div 4 = 1.75$

With more men, the hours taken to repair a road will be even shorter.

So next divide 6 by 1.75.
$6 \div 1.75 = 3.43$

Answer : It'll take 3.43 hours to do the job if they work at the same rate.

Hope this helps. - M

4 0

4 years ago

Whats the domain and range?

kirill [66]

In its simplest form the domain is all the values that go into a function, and a range is all the values that come out.

6 0

3 years ago

Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?

Artemon [7]

Answer:

The equation $y=\frac{-x^2-6x+31}{8}$ represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula $d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }$ , we find that the distance between (x, y) is

$\sqrt{(x+3)^2+(y-3)^2}$

and the distance between (x, y) and the directrix y = 7 is

$\sqrt{(y-7)^2}$ .

On the parabola, these distances are equal so, we solve for y:

$\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}$