<span>a.) Let x be the number of tickets sold before the event and y the number of tickets sold on the day of the event. Then x + y =< 800 and 6x + 9y >= 5000. (b.) Suppose the club sold 440 tickets before the event, i.e. x = 440, maximum number of tickets remaining to be sold = 800 - 440 = 360. Maximum amount realized from the sales supposing all tickets were sold = 6(440) + 9(360) = 2640 + 3240 = $5880 which is greater than $5000. Therefore, it is possible for the club to sell enough additional tickets on the day of the show to meet the expenses of the show.</span>
Step-by-step explanation:
option C . they are borrowing your money and rewarding you for keeping money with them
Step-by-step explanation:
a. h(0) = 1 - 4* 0 - 0² = 1-0 = 1
b. h(-4) = 1 - 4 * (-4) - (-4)² = 1 + 16 -16 = 1
c. h(10) = 1 - 4 * 10 - (10)² = 1 - 40 - 100 = -139
d. h (3/2) = 1 - 4 * 3/2 - (3/2)²
= 1 -6 - 9/4
= ( 4 - 24 - 9 ) / 4
= - 29/ 4
Hope it helps :)
Answer:
Step-by-step explanation:
This is a typical problem of u.a.r.m. ( uniformly accelerated rectilinear motion). Let's take an eye on the u.a.r.m. equations:

We know the runner started from rest so we can discard
as 
Also we can consider she starts at
.
All we have to do now is replace these values at our equations to obtain:

As we are told that the acceleration remains constant, we can then find the time it took for her to run the whole distance as follows:
First we note that the ratio between her velocity and the time it takes for her to run a certain distance is constant. This is:

In particular, if we take
where
is the total time it takes for her to run the whole distance 
We know that at this point the velocity is:

So that:

Now we can replace this in the equation of motion 

Where we finally find that
