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3 years ago

12

URGENT !!!!!!!!! Please answer correctly !!!!! Will be marking Brianliest !!!!!!!!!!!!!!!!

1 answer:

Morgarella [4.7K]3 years ago

8 0

-2/5
Step by Step :
18 - 8 = 10
-15 - 10 = -25
10/-25 = -2/5

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A high school drama club is putting on their annual theater production. There is a maximum of 800 tickets for the show. The cost

astra-53 [7]

<span>a.) Let x be the number of tickets sold before the event and y the number of tickets sold on the day of the event. Then x + y =< 800 and 6x + 9y >= 5000. (b.) Suppose the club sold 440 tickets before the event, i.e. x = 440, maximum number of tickets remaining to be sold = 800 - 440 = 360. Maximum amount realized from the sales supposing all tickets were sold = 6(440) + 9(360) = 2640 + 3240 = $5880 which is greater than $5000. Therefore, it is possible for the club to sell enough additional tickets on the day of the show to meet the expenses of the show.</span>

3 0

2 years ago

Solve the equation 12a3 + 12a2 = -3a. Show all work.

Artist 52 [7]

12a³ + 12a² = -3a | + 3a

12a³ + 12a² + 3a = 0

3a(4a² + 4a + 1) = 0

3a(2a + 1)² = 0

3a = 0 or (2a + 1)² = 0

1) 3a = 0 | : 3

a = 0

2) (2a + 1)² = 0

2a + 1 = 0 | - 1

2a = -1 | : 2

a = -1/2

a ∈ {-1/2, 0}

Used formula:

(a + b)² = a² + 2ab + b²

7 0

3 years ago

Why do banks pay you interest?

Anastasy [175]

Step-by-step explanation:

option C . they are borrowing your money and rewarding you for keeping money with them

6 0

2 years ago

Will Give Brainliest if Correct

Olenka [21]

Step-by-step explanation:

a. h(0) = 1 - 4* 0 - 0² = 1-0 = 1

b. h(-4) = 1 - 4 * (-4) - (-4)² = 1 + 16 -16 = 1

c. h(10) = 1 - 4 * 10 - (10)² = 1 - 40 - 100 = -139

d. h (3/2) = 1 - 4 * 3/2 - (3/2)²

= 1 -6 - 9/4

= ( 4 - 24 - 9 ) / 4

= - 29/ 4

Hope it helps :)

6 0

3 years ago

A runner maintains constant acceleration after starting from rest as she runs a distance of 60.0 m. The runner's speed at the en

Svet_ta [14]

Answer: $\frac{40}{3}s$

Step-by-step explanation:

This is a typical problem of u.a.r.m. ( uniformly accelerated rectilinear motion). Let's take an eye on the u.a.r.m. equations:

$v(t) = v_{0} + a.t\\x(t) = x_{0} + v_{0}.t + \frac{1}{2}.a.t^{2}$

We know the runner started from rest so we can discard $v_{0}$ as $v_{0} = 0$

Also we can consider she starts at $x_{0} = 0$ .

All we have to do now is replace these values at our equations to obtain:

$v(t) = a.t\\x(t) = \frac{1}{2}.a.t^{2}$

As we are told that the acceleration remains constant, we can then find the time it took for her to run the whole distance as follows:

First we note that the ratio between her velocity and the time it takes for her to run a certain distance is constant. This is:

$\frac{v(t)}{t} = a ; \forall t$

In particular, if we take $t=t_{f}$ where $t_{f}$ is the total time it takes for her to run the whole distance $x(t=t_{f})=60m$

We know that at this point the velocity is:

$v(t=t_{f}) = 9\frac{m}{s}$

So that:

$a = \frac{v(t=t_{f})}{t_{f}} = \frac{9\frac{m}{s}}{t_{f}}$

Now we can replace this in the equation of motion $x(t)$

$x(t=t_{f}) = \frac{1}{2}.a.t^{2} = \frac{1}{2}.\frac{9\frac{m}{s}}{t_{f}}.t_{f}^{2} = 60m$

Where we finally find that

$t_{f} = \frac{40}{3}s$

3 0

3 years ago

Read 2 more answers