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bija089 [108]
3 years ago
12

Factor completely x^2-48

Mathematics
1 answer:
fredd [130]3 years ago
5 0

Answer: (x-7)(x+7)


Step-by-step explanation:

To solve this problem you must apply the proccedure shown below;

- Make the equation equal to zero:

x^{2}-49=0

-Add 49 at both sides:

x^{2}=49

- Now, you must take the square root of both sides of the equation, then you obtain the following roots:

x=\sqrt{49}\\x_1=7\\x_2=-7

- Then you have:

x^{2}-49=(x-7)(x+7)

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Find all polar coordinates of point P where P = ordered pair 3 comma negative pi divided by 3 .
jek_recluse [69]

Answer:

The all polar coordinates of P are:

(3 , -π/3) , (3 , 5π/3) , (-3 , 2π/3) , (-3 , -4π/3)

Step-by-step explanation:

* Lets study the polar coordinates of a point

- In polar coordinates there is an infinite number of coordinates

 for a given point.

- The polar coordinates of a point (x , y) is (r , θ), where

  r = √ ( x2 + y2 )

  θ = tan-1 ( y / x )

# Ex: the following four points are all coordinates for the same point.

* (5 , π/3) = (5 , −5π/3) = (−5 , 4π/3) =(−5 , −2π/3)

- These four points only represent the coordinates of the point without  

  rotating more than once

- So the point (r,θ) can be represented by any of the following

  coordinate pairs  (r , θ + 2π n) and (−r , θ + (2n + 1) π), where n is

  any integer.

* Now lets solve the problem

∵ P = (3 , -π/3)

∵ (r , θ + 2πn)

∴ r = 3 an d Ф = -π/3

- let n = 1

∴ P = (3 , -π/3 + 2π)

∴ P = (3 , 5π/3)

∵ P =(3 , -π/3)

∵ P = (-r , θ + (2n + 1) π)

Let n = 0

∴ P = (-3 , -π/3 + (2×0 + 1) π)

∴ P = (-3 , -π/3 + (0 + 1) π)

∴ P = (-3 , -π/3 + π)

∴ P = (-3 , 2π/3)

∵ P =(3 , -π/3)

∵ P = (-r , θ + (2n + 1) π)

Let n = -1

∴ P = (-3 , -π/3 + (2(-1) + 1) π)

∴ P = (-3 , -π/3 + (-2 + 1) π)

∴ P = (-3 , -π/3 + -π) = (-3 , -4π/3)

∴ P = (-3 , -4π/3)

5 0
2 years ago
3^4 + 3 x 5 =<br> (the '^4' is an exponent)
Vesnalui [34]

Answer:

96

Step-by-step explanation:

3^4 = 3*3*3*3 = 9*9= 81

3*5=15

81 + 15 = 96

Hope this helps!!

4 0
2 years ago
Read 2 more answers
Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

3 0
3 years ago
Solve the equation |t+8|=5
vodka [1.7K]

We have t+8=5 or t+8=-5

So t1 = -3 and t2 = -13

4 0
3 years ago
(x+6)(x+3) = x(x+6)+(x+6)(3)<br> Whats the froof here ?
natulia [17]

Answer:

I'm confused as you are

4 0
3 years ago
Read 2 more answers
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