Question

Which trigonometric ratios are correct for triangle DEF? Select three options.

Answer 1

Answer:

The correct options are 1, 3 and 4.

Step-by-step explanation:

Consider the below figure attached with this question.

From the figure it is clear that DF = 7 units and EF = 24 units.

According to the Pythagoras theorem, in a right angled triangle

$hypotenuse^2=perpendicular^2+base^2$

Using Pythagoras theorem, we get

$D E^2=E F^2+D F^2$

$D E^2=24^2+7^2$

$D E^2=625$

Taking square root on both sides.

$D E=25$

In a right angle triangle

$\sin \theta = \dfrac{opposite}{hypotenuse}$

$\cos \theta = \dfrac{adjacent}{hypotenuse}$

$\tan \theta = \dfrac{opposite}{adjacent}$

Using these ratio we get

$\sin (D)=\dfrac{EF}{DE}=\dfrac{24}{25}$

$\cos (E)=\dfrac{EF}{DE}=\dfrac{24}{25}$

$\tan (D)=\dfrac{EF}{DF}=\dfrac{24}{7}$

$\sin (E)=\dfrac{DF}{DE}=\dfrac{7}{25}$

Therefore, the correct options are 1, 3 and 4.

Answer 2

Answer: I think the answer is B

Step-by-step explanation: