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2 years ago

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Jack and Jim went biking. Jack biked for 5 1/3 hours with average speed 12 1/2 miles per hour. Jim traveled exactly 1 1/5 as far

as Jack did. How long was Jim’s trip?

1 answer:

ahrayia [7]2 years ago

3 0

Given that Jack biked for $5 \frac{1}{3}$ hours with an average speed of $12 \frac{1}{2}$ miles per hour.

The distance travelled by Jack is given by

$d=speed\times time \\ \\ =12 \frac{1}{2}\times5 \frac{1}{3}= \frac{25}{2} \times \frac{16}{3} \\ \\ = \frac{200}{3} =66 \frac{2}{3} \ miles$

Given that Jim travelled exactly $1 \frac{1}{5}$ as far as Jack did, then the distance Jim travelled is given by

$d=1 \frac{1}{5} \times66 \frac{2}{3} \\ \\ = \frac{6}{5} \times \frac{200}{3} =80$

Therefore, the length of Jim's journey is 80 miles.

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A soccer ball is kicked toward the goal. The height of the ball is modeled by the function h(t) = −16t2 + 48t where t equals the

Stolb23 [73]

Answer:

t = 1.5; it takes 1.5 seconds to reach the maximum height and 3 seconds to fall back to the ground.

Explanation:

<u>1) Explanation of the model:</u>

Given: h(t) = -16t² + 48t

This is a quadratic function, so the height is modeled by a patabola.

This means that it has a vertex which is the minimum or maximu, height. Since the coefficient of the leading (quadratic) term is negative, the parabola opens downward and the vertex is the maximum height of the soccer ball.

<u>2) Axis of symmetry:</u>

The axis of symmetry of a parabola is the vertical line that passes through the vertex.

In the general form of the parabola, ax² + bx + c, the axis of symmetry is given by x = -b/(2a)

In our model a = - 16, and b = 48, so you get: t = - ( 48) / ( 2 × (-16) ) = 1.5

<u>Conclusion</u>: since t = 1.5 is the axys of symmetry, it means that at t = 1.5 the ball reachs its maximum height and that it will take the same additional time to fall back to the ground, whic is a tolal of 1. 5 s + 1.5 s = 3.0 s.

Answer: t = 1.5; it takes 1.5 seconds to reach the maximum height and 3 seconds to fall back to the ground.

8 0

2 years ago

Please help! I dont understand! Thank you

Digiron [165]

QUESTION A

The given inequality is

$x-1\:>\:5$

Add 1 to both sides of the inequality to obtain;

$x\:>\:5+1$

$x\:>\:6$

Answer: 2. $x\:>\:6$ , open dot at 6 and shaded to the right.(A)

QUESTION B.

The given inequality is $2x \le 6$ .

Divide both sides by 2;

$x \le \frac{6}{2}$ .

$x \le 3$ .

Answer: 5. $x \le 3$ , closed dot at 3 and shaded to the left(B).

QUESTION C

The given inequality is $x-7\:>\:-4$

Add 7 to both sides to get;

$x\:>\:-4+7$

$\Rightarrow x\:>\:3$

Answer: 7. $x\:>\:3$ , open dot at 3 and shaded to the right.(C)

QUESTION D

We want to solve;

$-2x \:$

Divide through by -2 and reverse the inequality sign;

$x \:>\:\frac{6}{-2}$

$x \:>\:-3$

Answer; 3. $x \:>\:-3$ Open dot at -3 and shaded to the right. (D)

QUESTION E

We have

$4\:$

Divide through by -4 and reverse the sign.

$\frac{4}{-4}\:>\:x$

$-1\:>\:x$

or

$x\:$

Answer: 6. $x\:$ open dot at -1, and shaded to the left(E)

QUESTION F

The given inequality is $-2x+3\:$

Add -3 to both sides to get;

$-2x\:$

$-2x\:$

Divide both sides of the inequality by -2 and reverse the sign;

$x\:>\:5$

Answer:9. $x\:>\:5$ , open dot at 5 and shaded to the right(F)

QUESTION G

The given inequality is

$5x+1\ge11$

$5x\ge11-1$

$5x\ge10$

Divide by 5

$x\ge2$

Answer ; 10. $x\ge2$ , closed dot at 2 and shaded to the right(G)

QUESTION H

We have $3(x+4)\:>\:8x-6$

Expand the bracket to get;

$3x+12\:>\:8x-6$

Group similar terms to get;

$3x-8x\:>\:-6-12$

Simplify

$-5x\:>\:-18$

Divide through by -5 and reverse the sign;

$x\:$

Answer: 1. $x\:$ Open dot at 18/5 and shaded to the left(H)

QUESTION I

We have $-3x+4\:$ .

$-3x+x\:$

$-2x\:$

Divide by -2 and reverse the sign;

$x\:>\:1$

Answer: 8. $x\:>\:1$ , open dot at 1 and shaded to the right(I)

J. The given inequality $-2(x-4)\:>\:5-(x+2)$

Expand the bracket to get;

$-2x+8\:>\:5-x-2$

Group like terms to get;

$-2x+x\:>\:5-2-8$

$-x\:>\:-5$

Divide by -1 and reverse the sign to get;

$x\:$

Answer; 4. $x\:$ , open dot at 5 and shaded to the left.(J)

6 0

3 years ago

Angle 1 and angle 2 form a linear pair.if m angle =5x+9 and m angle 2=3x+11,find the measures of both angels.

lbvjy [14]

Answer: ∠1 = 109° ∠2 = 71°

<u>Step-by-step explanation:</u>

If the two angles form a linear pair, then their sum is 180°

∠1 + ∠2 = 180°

(5x + 9) + (3x + 11) = 180

8x + 20 = 180

8x = 160

x = 20

∠1 = 5x + 9

= 5(20) + 9

= 100 + 9

= 109

∠2 = 3x + 11

= 3(20) + 11

= 60 + 11

= 71

<u> CHECK:</u>

∠1 + ∠2 = 180°

109° + 71° = 180°

180° = 180° $\checkmark$

7 0

3 years ago

-10 + 20p + 6p = -16

pshichka [43]

Answer: p= -3/13

Step-by-step explanation:

-10+26p=-16

+10 +10

26p =-6

26 26

p= -3/13

6 0

3 years ago

What are two ratios that are equivalent to 9/12

Gnom [1K]

Find the greatest common factor (GCF) of 9 and 12 using factor trees. The GCF is 3

Divide each term (9 and 12) over 3
9/3 = 3
12/3 = 4

So 9/12 reduces to 3/4

In other words, 9/12 = 3/4

--------------------------------------

Now focusing on 3/4, we can multiply top and bottom by the same value. Let's say we multiply top and bottom by 5

3*5 = 15
4*5 = 20

So 3/4 = 15/20

--------------------------------------

So two ratios equivalent to 9/12 are 3/4 and 15/20. There are infinitely other ratios that are equivalent.

In short, the answers are 3/4 and 15/20.

6 0

3 years ago

Read 2 more answers