The isotope that is more abundant, given the data is isotope Li7
<h3>Assumption</h3>
- Let Li6 be isotope A
- Let Li7 be isotope B
<h3>How to determine whiche isotope is more abundant</h3>
- Molar mass of isotope A (Li6) = 6.02 u
- Molar mass of isotope B (Li7) = 7.02 u
- Atomic mass of lithium = 6.94 u
- Abundance of A = A%
- Abundance of B = (100 - A)%
Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]
6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]
6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]
6.94 = [6.02A% + 702 - 7.02A%] / 100
Cross multiply
6.02A% + 702 - 7.02A% = 6.94 × 100
6.02A% + 702 - 7.02A% = 694
Collect like terms
6.02A% - 7.02A% = 694 - 702
-A% = -8
A% = 8%
Thus,
Abundance of B = (100 - A)%
Abundance of B = (100 - 8)%
Abundance of B = 92%
SUMMARY
- Abundance of A (Li6) = 8%
- Abundance of B (Li7) = 92%
From the above, isotope Li7 is more abundant.
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THe Answer is 105 J
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Answer:
It is the second option.
Explanation:
The conversion factor is:
I kPa = 7.50062 Torr.
Answer:
55.52°
Explanation:
Concept tested: Sine rule of triangles
We need to know the sine rule
- According to sine rule, if the three sides of a triangle are a, b and c and the corresponding angles, A, B and C
- Then,

In this case;
- If we take, a = 5.7 units and A = 70°, and
b= 5 units, B = x°
- Using the sine rule we can find the value of x
Therefore;

Then;



Therefore, X = 55.52°
Therefore, the value of x in the triangle is 55.52°