A 260.0 −mL buffer solution initially contains 2.5×10−2 M of HCHO2 and 2.5×10−2 M of NaCHO2
1 answer:
The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Data;
- Volume of solution = 260mL
- conc. of HCHO2 = 2.5*10^-2M
- conc. of NaCHO2 = 2.5*10^-2M
To calculate the mass of reagent added, let's start with HCHO2
The mass of HCHO2 to be added is the number of moles of HCHO2 multiplied by it's molar mass.
The mass of NaCHO2 to be added in the buffer solution is
The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Learn more about buffer solution here;
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<h3>The answer is 1.04 g/mL</h3>Explanation:
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<h3>1.04 g/mL</h3>Hope this helps you
Explanation: In IUPAC, E-Z convention is given for describing the cis - trans notation to the isomers. According to CIP rule, the groups on the doubly bonded carbon atoms are given priorities based on the the atomic masses of first connected atom.
If the highest priority groups are on the same side, it is known as Z-form and if the highest priority groups are on opposite side, it is known as E-form.
We are given (Z)-3-bromo-6-methyl-2-heptene, in this the highest priority groups are bromine on one side and methyl- group on another side.
The structure is provided in the image below.
