Question

A 260.0 −mL buffer solution initially contains 2.5×10−2 M of HCHO2 and 2.5×10−2 M of NaCHO2

Answer 1

The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively

Data;

• Volume of solution = 260mL
• conc. of HCHO2 = 2.5*10^-2M
• conc. of NaCHO2 = 2.5*10^-2M

Mass of Reagent Added

To calculate the mass of reagent added,  let's start with HCHO2

The mass of HCHO2 to be added is the number of moles of HCHO2 multiplied by it's molar mass.

$260*10^-^3 * 2.5*10^-^2 * 46 = 0.229 = 0.23g$

The mass of NaCHO2 to be added in the buffer solution is

$260*10^-^3*2.5*10^-^2*68 = 0.442 = 0.44g$

The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively

Learn more about buffer solution here;

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