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matrenka [14]
3 years ago
15

​Recently, More Money 4U offered an annuity that pays 5.7 % compounded monthly. If $1,011 is deposited into this annuity every​

month, how much is in the account after 6​years? (Round to the nearest dollar) Part 2 of the question: How much of this is​ interest? (Round to the nearest dollar)
Mathematics
1 answer:
Tresset [83]3 years ago
6 0
Recall that the future value (FV), of an annuity payment of $P, for, n years at, t times a year at, r% interest compounded, t times a year is given by
FV=P \frac{\left(1+ \frac{r}{t} \right)^{nt}-1}{\frac{r}{t}}

Given that <span>More Money 4U offered an annuity that pays r = 5.7% = 0.057 compounded monthly (12 times a year or t = 12). If P = $1,011 is deposited into this annuity every​ month (t = 12), then after n = 6 years the amount in the account is given by:
FV=1,011\times \frac{\left(1+ \frac{0.057}{12} \right)^{6\times12}-1}{\frac{0.057}{12}} \\  \\ =1,011\times \frac{(1+0.00475)^{72}-1}{0.00475} =1,011\times \frac{(1.00475)^{72}-1}{0.00475}  \\  \\ =1,011\times \frac{1.406621-1}{0.00475} =1,011\times \frac{0.406621}{0.00475} =1,011\times85.6044 \\  \\ =\$86,546.05

Therefore, </span>the amount in <span>the account after 6​years rounded to the nearest dollar is $86,546.


PART 2:
Given that </span><span>$1,011 is deposited into this annuity every​ month for 6 years, the amount deposited into the account is given by
$1,011 x 12 x 6 = $72,792

Therefore, the amount of interest accrued is given by
$86,546 - $72,792 = $13,754

Therefore, the amount of interest received is $13,754
</span>
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Dado que unos tambores, con una etiqueta de 30 L, son llenados con una solución proveniente de una tina grande, y se agrega una cantidad aleatoriamente de la solución en cada tambor con media de 30.01 L y desviación estándar de 0.1 L, para determinar A) ¿Cuál es la probabilidad de que la cantidad total de la solución contenida en 50 tambores sea mayor a 1 500 L?; B) Si la cantidad total de la solución en la tina es de 2 401 L, ¿cuál es la probabilidad de que puedan llenarse 80 tambores sin que se acabe la solución?; y C) ¿Cuánta solución debe contener la tina para que la probabilidad sea 0,9 de que puedan llenarse 80 tambores sin que se acabe la solución?, se deben realizar los siguientes cálculos:

A)

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B)

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C)

  • (80 x 30) x 0.9 = X
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Aprende más sobre desviación estándar en brainly.com/question/12402189

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