Question

Use what you know about the difference of squares and the product of a perfect square binomial to expand the following.

Answer 1

Answer:

$\boxed{x^2 - 6x + 9 - y^2}.$

Step-by-step explanation:

We start by applying the difference of squares to the expression:

$((x-3)-y)((x-3)+y) = (x-3)^2 - y^2.$

Now we apply the square of a binomial to the first term:

$(x-3)^2 - y^2 = x^2 - 2 \times 3 \times x + 3^2 - y^2 = x^2 - 6x + 9 - y^2.$

So the answer is:

$\boxed{x^2 - 6x + 9 - y^2}.$