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sukhopar [10]
3 years ago
15

Algebra question (eristhestar please help me)

Mathematics
1 answer:
Svetllana [295]3 years ago
7 0
If it says five more than it means the 5 is after, and quantity of a number means it’s in parentheses so it would have to be C.
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Calculate the length of ed and be
pashok25 [27]

Answer:

ED = 6.5 cm

BE = 14.4 cm

Step-by-step explanation

AB/BC = AE/ED is less than or eqauls ED = BC×AE/AB

so

ED = 5×26/20 = 130/20 = 6.5 cm

and

AB/AC = BE/CD => BE = AB×CD/AC

so

BE = 20×18/25 = 360/25 = 14.4 cm

4 0
2 years ago
What is the approximate area of the circle? Use A. 17.6 square inches B. 24.6 square inches C. 35.2 square inches D. 98.5 square
anygoal [31]
There should have been an attached image.

Area of a circle is can only be computed when the radius or diameter is provided.

Area of a circle = π r²

Based on the image I saw, the radius is 5.6 inches

A = 3.14 * (5.6in)²
A = 3.14 * 31.36 in²
A = 98.47 in² ⇒ CHOICE D. 98.5 square inches.
6 0
3 years ago
Masud makes 8 gallons of punch. How many cups of punch does he make?
PIT_PIT [208]

Answer:

Step-by-step explanation:

Its 1gallon= 4 quarts because 8 gallons is 128 cups and 128 cups makes 4 quarts

3 0
3 years ago
What is the greatest prime you must consider to test whether 2114 is​ prime?
IceJOKER [234]

Answer:

2114 is not a prime number because you can divide to 7. Prime number mean is the prime number is the number that can be divided by the number it self

4 0
3 years ago
A certain change in a process for manufacture of component parts is being considered. Samples are taken using both the existing
Katyanochek1 [597]

Answer:

a) The confidence interval is 0.00\leq\pi_1-\pi_2\leq0.02.

Step-by-step explanation:

We have to calculate a confidence interval (CI) of a difference of proportions.

For the existing procedure, the proportion is:

p_1=75/1500=0.05

For the new procedure, the proportion is:

p_2=80/2000=0.04

To calculate the CI, we need to estimate the standard deviation

s=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2} }\\\\s=\sqrt{\frac{0.05(1-0.05)}{1500} +\frac{0.04(1-0.04)}{2000} }=\sqrt{ 0.000032 + 0.000019 }=\sqrt{  0.000051 }\\\\s=0.007

For a 90% CI, the z-value is 1.64.

Then, the CI is:

(p_1-p_2)-z*\sigma \leq\pi_1-\pi_2\leq(p_1-p_2)+z*\sigma \\\\(0.05-0.04)-1.64*0.007\leq\pi_1-\pi_2\leq(0.05-0.04)+1.64*0.007\\\\0.01-0.01\leq\pi_1-\pi_2\leq0.01+0.01\\\\0.00\leq\pi_1-\pi_2\leq0.02

6 0
3 years ago
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