Kyra solved the following quadratic equation. What was the error, if any, that she made?

How much money will Rachel have in her account in ten years

ryzh [129]

200(1+0.03)^20==361.22

3 0

2 years ago

A shipment to the warehouse has 4500 mp3 players 50 random samples are tested and 3 are defective how many defective mp3 players

nikitadnepr [17]

Answer:

4447.... i think

Step-by-step explanation:

5 0

2 years ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

2 years ago

An adult takes 800 mg of ibuprofen. Each hour, the amount of ibuprofen in the person's

ss7ja [257]

Answer:

116.31468544 mg ibuprofen left

Step-by-step explanation:

Since there are 800 mg at the beginning and the system decreases by about 32% of the ibuprofen

After 1 hour

→ 800 - (800x32/100) = 800 - 256 = 544 mg ibuprofen left

After 2 hours

→ 544 - (544x32/100) = 544 - 174.08 = 369.92 mg ibuprofen left

After 3 hours

→ 369.92 - (369.92x32/100) = 369.92 - 118.3744 = 251.5456 mg ibuprofen left

After 4 hours

→ 251.5456 - (251.5456x32/100) = 251.5456 - 80.494592 = 171.051008 mg ibuprofen left

After 5 hours

→ 171.051008 - (171.051008x32/100) = 171.051008 - 54.73632256 = 116.31468544 mg ibuprofen left

3 0

3 years ago

What’s the algebraic expression to this please help !!!!

Wewaii [24]

2 × c ÷ 7 ÷ 2. This better?

8 0

3 years ago