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aleksley [76]
4 years ago
11

How can one fourthx − 3 =one halfx + 8 be set up as a system of equations?

Mathematics
2 answers:
julia-pushkina [17]4 years ago
6 0
The answer is B hope this help u
GarryVolchara [31]4 years ago
3 0

Answer:

4y − x = −12

2y − x = 16

Step-by-step explanation:

Given : \frac{1}{4}x-3=\frac{1}{2}x+8

We get,

\frac{1}{4}x-3=y   ..........(1)

\frac{1}{2}x+8=y .....(2)

Multiply equation (1) by 4 , we get,

x-12=4y

or 4y-x= -12

Now, multiply equation (2) by 2 , we get,

x+16=2y

or 2y-x= 16

Hence, option B is correct.

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Step-by-step explanation:

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so

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