Question

How can one fourthx − 3 =one halfx + 8 be set up as a system of equations?

Answer 1

The answer is B hope this help u

Answer 2

Answer:

4y − x = −12

2y − x = 16

Step-by-step explanation:

Given : $\frac{1}{4}x-3=\frac{1}{2}x+8$

We get,

$\frac{1}{4}x-3=y$   ..........(1)

$\frac{1}{2}x+8=y$ .....(2)

Multiply equation (1) by 4 , we get,

$x-12=4y$

or $4y-x= -12$

Now, multiply equation (2) by 2 , we get,

$x+16=2y$

or $2y-x= 16$

Hence, option B is correct.