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dem82 [27]
3 years ago
5

How could you identify an equation as being a "difference of two squares"? *

Mathematics
1 answer:
Anarel [89]3 years ago
6 0

Answer:

Step-by-step explanation:

The first one.

You would be subtracting two perfect squares.

A^2 - B^2 = 0

That is the formula for a quadratic difference of squares equation to find zeros.

Hope this helps!

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HELPP!!what is the answer to this picture above^
nasty-shy [4]

Answer:

\fbox{ \fbox { \sf{Distance  =  \sf{15 \: units}}}}

{ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}

Step-by-step explanation:

\star{ \:  \sf { \: Let \: the \: points \: be \: A \: and \: B}}

\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}

\underline{ \underline{ \tt{Finding \: the \: distance}}}

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(18 - 6)}^{2}  +  {(15 - 6)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(12)}^{2}  +  {(9)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{144 + 81}}}

\mapsto{ \sf{Distance =  \sqrt{225} }}

\mapsto{ \sf{Distance =  \sqrt{ {15}^{2} } }}

\mapsto{  \boxed{\sf{Distance = 15 \: units}}}

\underline{ \underline {\tt{Finding \: the \: Midpoint}}}

\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2}  \: , \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2}  \: , \:  \frac{6 + 15}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{24}{2}  \: , \:  \frac{21}{2} )}}

\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

3 0
3 years ago
Help me please<br>help me please​
Nikolay [14]

Answer:

1 second

Step-by-step explanation:

s=-5\\u=0\\v=\\a=-10\\t=t

\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac12at^2\\ \implies -5 & =(0)t+\dfrac12(-10)t^2\\ -5 & = -5t^2\\ t^2& = 1\\ t & = \pm\sqrt{1}\\ t & = 1\: \sf s\end{aligned}

7 0
2 years ago
Can u solve it i dunno how:)​
pshichka [43]

Answer:

Step-by-step explanation

I think it is $170 a month.

Is subtracted 8,500-6,460 and that gave me 2,040.

I divided that by 12 and it gave me 170

6 0
3 years ago
Read 2 more answers
Find the area of the square if the circumference of the circle is 32.97 in
Ivanshal [37]

Answer: 86.5 in²

Step-by-step explanation: Circumference is2·pi·r= 32.97 in.

Radius r = 32.97 in/ 2pi = 5.247 in. Area is pi·r²

4 0
3 years ago
A box of 12 Popsicles costs $4.44 what is the Popsicles unit rate
OLEGan [10]
The unit rate would be $0.37
4 0
3 years ago
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