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3 years ago

5

How could you identify an equation as being a "difference of two squares"? *

1 answer:

Anarel [89]3 years ago

6 0

Answer:

Step-by-step explanation:

The first one.

You would be subtracting two perfect squares.

A^2 - B^2 = 0

That is the formula for a quadratic difference of squares equation to find zeros.

Hope this helps!

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HELPP!!what is the answer to this picture above^

nasty-shy [4]

Answer:

$\fbox{ \fbox { \sf{Distance = \sf{15 \: units}}}}$

${ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}$

Step-by-step explanation:

$\star{ \: \sf { \: Let \: the \: points \: be \: A \: and \: B}}$

$\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}$

$\underline{ \underline{ \tt{Finding \: the \: distance}}}$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(18 - 6)}^{2} + {(15 - 6)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(12)}^{2} + {(9)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{144 + 81}}}$

$\mapsto{ \sf{Distance = \sqrt{225} }}$

$\mapsto{ \sf{Distance = \sqrt{ {15}^{2} } }}$

$\mapsto{ \boxed{\sf{Distance = 15 \: units}}}$

$\underline{ \underline {\tt{Finding \: the \: Midpoint}}}$

$\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2} \: , \: \frac{6 + 15}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{24}{2} \: , \: \frac{21}{2} )}}$

$\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

3 0

3 years ago

Help me please<br>help me please

Nikolay [14]

Answer:

1 second

Step-by-step explanation:

$s=-5\\u=0\\v=\\a=-10\\t=t$

$\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac12at^2\\ \implies -5 & =(0)t+\dfrac12(-10)t^2\\ -5 & = -5t^2\\ t^2& = 1\\ t & = \pm\sqrt{1}\\ t & = 1\: \sf s\end{aligned}$

7 0

2 years ago

Can u solve it i dunno how:)

pshichka [43]

Answer:

Step-by-step explanation

I think it is $170 a month.

Is subtracted 8,500-6,460 and that gave me 2,040.

I divided that by 12 and it gave me 170

6 0

3 years ago

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Find the area of the square if the circumference of the circle is 32.97 in

Ivanshal [37]

Answer: 86.5 in²

Step-by-step explanation: Circumference is2·pi·r= 32.97 in.

Radius r = 32.97 in/ 2pi = 5.247 in. Area is pi·r²

4 0

3 years ago

A box of 12 Popsicles costs $4.44 what is the Popsicles unit rate

OLEGan [10]

The unit rate would be $0.37

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3 years ago

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