Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.55 μC charge and flies due west at a speed of
1 answer:
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The Average velocity for the bacterium is 0.75 unit/sec.
<u>Explanation:</u>
The given values are in the vector form
Where,
dS = distance covered
dT = time interval
Now, to calculate distance covered, we have
&
d S=(4.6 i+1.9 k)-(2.2 i+3.7 j - 1.2 k)
d S=(4.6-2.2) i+(0-3.7) j+(1.9+1.2) k
d S=2.4 i-3.7 j+3.1 k
Now, putting these values in the standard formula to evaluate the average velocity, we get;
As dT=7.2 sec
Now,
Solving the equation, we get;
Hence, the average velocity for the bacterium is 0.75 unit/sec.
Answer:
k = 6,547 N / m
Explanation:
This laboratory experiment is a simple harmonic motion experiment, where the angular velocity of the oscillation is
w = √ (k / m)
angular velocity and rel period are related
w = 2π / T
substitution
T = 2π √(m / K)
in Experimental measurements give us the following data
m (g) A (cm) t (s) T (s)
100 6.5 7.8 0.78
150 5.5 9.8 0.98
200 6.0 10.9 1.09
250 3.5 12.4 1.24
we look for the period that is the time it takes to give a series of oscillations, the results are in the last column
T = t / 10
To find the spring constant we linearize the equation
T² = (4π²/K) m
therefore we see that if we make a graph of T² against the mass, we obtain a line, whose slope is
m ’= 4π² / k
where m’ is the slope
k = 4π² / m'
the equation of the line of the attached graph is
T² = 0.00603 m + 0.0183
therefore the slope
m ’= 0.00603 s²/g
we calculate
k = 4 π² / 0.00603
k = 6547 g / s²
we reduce the mass to the SI system
k = 6547 g / s² (1kg / 1000 g)
k = 6,547 kg / s² =
k = 6,547 N / m
let's reduce the uniqueness
[N / m] = [(kg m / s²) m] = [kg / s²]
Answer:
The number is
Explanation:
From the question we are told that
The wavelength is
The length of the glass plates is
The distance between the plates (radius of wire ) =
Generally the condition for constructive interference in a film is mathematically represented as
Where t is the thickness of the separation between the glass i.e
t = 0 at the edge where the glasses are touching each other and
t = 2d at the edge where the glasses are separated by the wire
m is the order of the fringe it starts from 0, 1 , 2 ...
So
=>
=>
given that we start counting m from zero
it means that the number of bright fringes that would appear is
=>
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