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3 years ago

Which type of transformer is found outside a residential house

1 answer:

7 0

The type of transformer that is found outside a residential house is :
step-down transformer
In step-down transformer, the secondary voltage is less than the primary voltage, which will reduce the voltage from the primary win.

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A jet aircraft is traveling at 262 m/s in hor-

NeTakaya

Solution :

Speed of the air craft, $S_a$ = 262 m/s

Fuel burns at the rate of, $S_b$ = 3.92 kg/s

Rate at which the engine takes in air, $S_{air}$ = 85.9 kg/s

Speed of the exhaust gas that are ejected relative to the aircraft, $S_{exh}$ =921 m/s

Therefore, the upward thrust of the jet engine is given by

$F=S_{air}(S_{exh}-S_a)+(S_b \times S_{exh})$

F = 85.9(921 - 262) + (3.92 x 921)

= 4862635.79 + 3610.32

= $4.8 \times 10^6 \ N$

Therefore thrust of the jet engine is $4.8 \times 10^6 \ N$ .

3 0

3 years ago

A 35 kg box rests on the back of a truck. The coefficient of static friction bet?005 (part 1 of 2)A 35 kg box rests on the back

elena-14-01-66 [18.8K]

Answer with Explanation:

We are given that

Mass of box=35 kg

Coefficient of static friction between box and truck bed=0.202

Acceleration due to gravity= $9.8 m/s^2$

a.We have to find the force by which the box accelerates forward.

Force by which box accelerates= $\mu mg=0.202\times 9.8\times 35$

Force by which box accelerates= $62.286 N$

b.We have to find the maximum acceleration can the truck have before the box slides.

Force =friction force

$ma=\mu mg$

$a=\mu g=9.8\times 0.202=1.9796 m/s^2$

Hence, the truck can have maximum acceleration before the box slide= $1.9796 m/s^2$

3 0

3 years ago

Enem 2003 embalagens longa vida brick

tresset_1 [31]

Answer:

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Explanation:

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3 0

3 years ago

How do muscles help the body move?

Finger [1]

Answer:

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A. The muscle contracts causing the tendon to pull the bone.

3 0

3 years ago

Read 2 more answers

The differences between microwaves and infrared radiation are due to differences in their _____.

Ket [755]

Answer:

15 V

Explanation:

From the question,

For series connection: (i) Both resistor have a common current flowing through the (ii) The combined resistance = R1+R2

Rt = R1+R2.................. Equation 1

Given: R1 = 5 ohms, R2 = 7.5 ohms.

Rt = 5+7.5 = 12.5 ohms.

Applying Ohm's law,

V = IRt................... Equation 2

Where V = Voltage, I = current.

make I The subject of the equation

I = V/Rt.............. Equation 3

Given: V = 25 V, Rt = 12.5 ohms.

Substitute into equation 3

I = 25/12.5

I = 2 A.

Now,

Voltage drop across the 7.5 ohms resistor = R2×I

Voltage drop across the 7.5 ohms resistor = 7.5×2

Voltage drop across the 7.5 ohms resistor = 15 V

8 0

3 years ago