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3 years ago

Convection occurs when thermal energy is transferred by the movement of

Physics

1 answer:

madam [21]3 years ago

6 0

Answer:

Convection is the transfer of thermal energy from one place to another by the movement of gas or liquid particles. How does this happen? As a gas or liquid is heated, the substance expands. This is because the particles in liquids and gases gain kinetic energy when they are heated and start to move faster.

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An object weighs 79.1 N in air. When it is suspended from a force scale and completely immersed in water the scale reads 21.8 N.

Free_Kalibri [48]

Answer:

(a). The density of the object is 1382 kg/m³.

(b). The density of the oil is 536.4 kg/m³.

Explanation:

Given that,

Weight in air = 79.1 N

Weight in water = 21.8 N

Weight in oil = 48.4 N

We need to calculate the volume of object

Using formula of buoyant force

$F_{b}=W_{air}=W_{water}$

$F_{b}=79.1-21.8$

$F_{b}=57.3\ N$

$F_{b}=\rho g h$

Put the value into the formula

$57.3=1000\times V\times 9.8$

$V=\dfrac{57.3}{1000\times9.8}$

$V=5.84\times10^{-3}\ m^3$

We need to calculate the density

Using formula of buoyant force

$F_{b}=\rho Vg$

$79.1=\rho\times5.84\times10^{-3}\times9.8$

$\rho=\dfrac{79.1}{5.84\times10^{-3}\times9.8}$

$\rho=1382\ kg/m^3$

The density of the object is 1382 kg/m³.

(b). We need to calculate the volume of object

Using formula of buoyant force

$F_{b}=W_{air}=W_{oil}$

$F_{b}=79.1-48.4$

$F_{b}=30.7\ N$

We need to calculate the density

Using formula of buoyant force

$F_{b}=\rho_{oil} Vg$

$30.7=\rho_{oil}\times5.84\times10^{-3}\times9.8$

$\rho_{oil}=\dfrac{30.7}{5.84\times10^{-3}\times9.8}$

$\rho=536.4\ kg/m^3$

The density of the oil is 536.4 kg/m³.

Hence, This is the required solution.

4 0

4 years ago

A 7.59-m-tall container is filled to the brim, partway with mercury and the rest of the way with water. The container is open to

hoa [83]

Answer:

0.22 m

Explanation:

$P_{o}$ = Atmospheric pressure = 101325 Pa

$P$ = Pressure at the bottom = tex]2 P_{o}[/tex] = 2 (101325) = 202650 Pa

$h$ = height of the container = 7.59 m

$x$ = depth of the mercury

Pressure at the bottom = Atmospheric pressure + Pressure due to mercury + Pressure due to water

$P = P_{o} + \rho _{w} g (h - x) + \rho _{hg} g x\\2 P_{o} = P_{o} + \rho _{w} g (h - x) + \rho _{hg} g x\\P_{o} = \rho _{w} g (h - x) + \rho _{hg} g x\\101325 = (1000) (9.8) (7.59 - x) + (13600) (9.8) x\\x = 0.22 m$