What was his average speed rate on his way to Seattle?
Ans: 62mph
On which part of his trip did he average a faster speed rate?
Ans: When he returned home.
With replacement:
P(C,V)=(12/40)(28/40)
P(C,V)=336/1600
P(C,V)=21/100
9514 1404 393
Answer:
59°
Step-by-step explanation:
Opposite angles of an inscribed quadrilateral are supplementary.
∠N +∠L = 180°
(a +16) +(a -18) = 180
2a = 182 . . . . . . . . . . add 2
a = 91 . . . . . . . . . . . . divide by 2
Then the measure of angle M is ...
∠M = (a+30)° = (91 +30)° = 121°
and angle K is its supplement.
∠K = 180° -121°
∠K = 59°
