Question

I NEED HELP PLEASE, THANKS! :)

Answer 1

Answer:

Option c

Step-by-step explanation:

We are being asked to find unit vector u given the direction as x = < 40, 9 >. In most cases it would be v =  < 40, 9 >, but it is the same concept.

To find the magnitude, given 40 and 9, you would do the following -

$| v | = \sqrt{40^2 + 9^2},\\| v | = \sqrt{1600 + 81},\\\\| v | = 41$

We got the magnitude to be 41. Now let us find unit vector u through the following calculations -

$u = < 40, 9 > / 41,\\u = < 40 / 41, 9 / 41 >$

And there you have it! The solution is option c!