Suppose AC = 5 cm, BC = 12 cm, and mAC = 45.2°.
2 answers:
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Answer:
6 feet
Step-by-step explanation:
Consider the right triangle formed by the wall, ladder and ground.
Let the distance the ladder is from the wall be d , then
Using Pythagoras' identity in the right triangle
The square on the hypotenuse ( ladder) is equal to the sum of the squares on the other 2 sides ( wall and d ), then
d² + 8² = 10²
d² + 64 = 100 ( subtract 64 from both sides )
d² = 36 ( take the square root of both sides )
d = = 6
That is the ladder is 6 feet away from the wall