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Leno4ka [110]
3 years ago
12

Let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes. If the random var

iable X is known to be exponentially distributed, what are the parameters of this exponential distribution
Mathematics
1 answer:
jeka57 [31]3 years ago
5 0

Answer:

The parameters of this exponential distribution is \lambda = \frac{1}{27} .

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes.

<u><em>So, X = time it takes for a person to choose a birthday gift</em></u>

The probability distribution function of exponential distribution is given by;

 f(x) = \lambda e^{-\lambda x}  , x >0      where, \lambda = parameter of distribution.

Now, the mean of exponential distribution is = \frac{1}{\lambda}  which is given to us as average value of 27 minutes that means  \lambda = \frac{1}{27} .

So, X ~ Exp( \lambda = \frac{1}{27} ) .

Therefore, the parameter of this exponential distribution is \lambda .

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

9m - m + 3 = -2(m + 1)

<u>Step 2: Solve for </u><em><u>m</u></em>

  1. Combine like terms:                    8m + 3 = -2(m + 1)
  2. Distribute -2:                                8m + 3 = -2m - 2
  3. Add 2m on both sides:                10m + 3 = -2
  4. Isolate <em>m</em> term:                             10m = -5
  5. Isolate <em>m</em>:                                      m = -1/2
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