The factors of the given model are (x+2) and (x+7)
Given the representation of the model expressed as;

To get the factors, we will factorize the given quadratic function as shown:

Group the functions to have;

Factor out the GCF from both parenthesis:

Hence the factors of the given model are (x+2) and (x+7)
Learn more on factorization here: brainly.com/question/25829061
Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is 
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Solution:</u></h3>
Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)
Generic slope intercept form of a line is given by y = mx + c
where "m" = slope of the line and "c" is the y - intercept
Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

We know that slopes of parallel lines are always equal
So the slope of line passing through (2, -2) is also 
Equation of line passing through
and having slope of m is given by


Substituting the values in equation of line we get



Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as 
Simplify the following:
(5 i^3 t^4)/7 - 2
i^3 = i^2×i = (-1) i = -i:
(5×-i t^4)/7 - 2
Put each term in (5 (-i) t^4)/7 - 2 over the common denominator 7:
(5 (-i) t^4)/7 - 2 = (-5 i t^4)/7 - 14/7:
(-5 i t^4)/7 - 14/7
(-5 i t^4)/7 - 14/7 = (-5 i t^4 - 14)/7:
Answer: (-5 i t^4 - 14)/7
6 and 2/8 is correct hope this helps.
Answer:
35m
Explanation:
Perimeter is the sum of all the sides of a shape, or a+b+c=P.
12m+8m+15m = 35m