I need help pleaseee ASAP! Will give brainliest to the correct answer :)

Mathematics

1 answer:

sp2606 [1]3 years ago

3 0

Answer:

7 rate of change. If right consider brainlist:)

Step-by-step explanation:

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Write the equation of a line that is perpendicular to y=0.25x-7y=0.25x−7y, equals, 0, point, 25, x, minus, 7 and that passes thr

Digiron [165]

Given equation of line y=0.25x-7.

On comparing given equation with slope-intercept form y=mx+b.

We get m=0.25.

0.25 could be written 25/100 in simplest fractions 1/4.

Line are perpendicular.

Therefore, slope of the perpendiular line would be reciprocal and opposite in sign of the given slope of the line.

Reciprocal of 1/4 is 4 and opposite of sign of 4 would be -4.

So, the slope of the required line is m=-4.

We are given a point (-6,8).

Applying point-slope form, we get

y-y1=m(x-x1)

y-8 = -4(x- (-6))

y-8 = -4(x+6)

y-8 = -4x -24.

Adding 8 on both sides, we get

y-8=8 = -4x -24+8

y=-4x-16.

Therefore, the equation y=-4x-16 is perpendicular to the given eqution of line.

8 0

3 years ago

100 points PLEASE ANSWER<br> ASAP thank you so much<br> Please show work

vivado [14]

Answer:

The mistake is that the equation on both sides is multiplied by 8. Both sides should be divided by 8.

Step-by-step explanation:

$8x^2-x-1=0$
$8x^2-x=1$ Divide both sides of the equation by 8
$x^2-\frac{1}{8} x=\frac{1}{8}$
$x^2-\frac{1}{8} x+?=\frac{1}{8} +?$ Add the same value to both side
$x^2-\frac{1}{8} x+\frac{1}{256} =\frac{1}{8} +\frac{1}{256}$
Use $a^2-2ab+b^2=(a-b)^2$
$(x-\frac{1}{16} )^2 = \frac{33}{256}$
$x-\frac{1}{16}=+-\frac{\sqrt{33} }{16}$
$x_{1} =\frac{-\sqrt{33}+1 }{16}$
$x_{2} =\frac{\sqrt{33}+1 }{16}$