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marissa [1.9K]
3 years ago
9

A2+2a-3=0 solving equations by completing the square

Mathematics
1 answer:
Olenka [21]3 years ago
8 0
I assume that you mean a^2 + 2a - 3 = 0

You need to find two numbers that multiply together to give the number 3 and when added give the answer 2 (as in 2a).  In this case the numbers are 3 and 1 (3 x 1 = 3 and 3 - 1 = 2)

Therefore we have
(a + 3)(a - 1) = 0

The values of x which solve the equation are -3 and 1
The reason is that -3 + 3 = 0 and 1 - 1 = 0 : zero times any number is zero


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3 years ago
What is the variable y in w= x y/z?
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3 years ago
Find sin 2x, cos 2x, and tan 2x from the given information.<br> cscx=4,tanx&lt;0.
lutik1710 [3]

Answer:

Step-by-step explanation:

Given the expression cosec (x) = 4 and tan(x)< 0

since cosec x = 1/sinx

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sinθ = opposite/hypotenuse

from sinx = 1/4

opposite = 1 and hypotenuse = 4

to get the adjacent, we will use the Pythagoras theorem

adj² = 4²-1²

adj² = 16-1

adj ²= 15

adj = √15

cosx = adj/hyp = √15/4

tanx = opposite/adjacent = 1/√15

since tan < 0, then tanx = -1/√15

From double angle formula;

sin2x = 2sinxcosx

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sin2x = 2√15/16

sin2x = √15/8

for cos2x;

cos2x = 1-2sin²x

cos2x = 1-2(1/4)²

cos2x = 1-2(1/16)

cos2x= 1-1/8

cos2x = 7/8

for tan2x;

tan2x  = tanx + tanx/1-tan²x

tan2x = 2tanx/1-tan²x

tan2x = 2(-1/√15)/1-(-1/√15)²

tan2x = (-2/√15)/(1-1/15)

tan2x = (-2/√15)/(14/15)

tan2x = -2/√15 * 15/14

tan2x = -30/14√15

tan2x = -30/7√15

rationalize

tan2x =  -30/7√15 * √15/√15

tan2x =  -30√15/7*15

tan2x =  -2√15/7

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Find an equation of the tangent line to the curve <br> xey + yex = 5
Harman [31]
I got:

<span>y′=(−y<span>e^−x</span>−e^y)/xe^y+e^x</span>
then plugged in x and y and got slope of (-5-e^5)
and ended with equation of y=(-5-e^5)x+5

I'm not sure with my solution though i hope this might help you.

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!
8 0
3 years ago
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