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storchak [24]
3 years ago
15

Which statement pertaining to system reliability is FALSE? Select one: A. Having the latest version of software products can mak

e your system more reliable. B. An accumulation of temporary Internet files has no effect on your computer's overall performance. C. You can clean out unnecessary programs from your Startup folder. D. When you defrag your hard drive, it works more efficiently.
Computers and Technology
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

Option(B) is the correct answer to the given question

Explanation:

System Reliability  means that the system is trust worthy and making work in the proper way.Following are the condition where system is reliable .

  • If we install the latest version of any software then that system is more reliable then the previous software.
  • If we delete the unnecessary and temporary files in the system the working of system is efficient and fast .
  • Defragmented  the hard drive in time to time it makes the system reliable.
  • Except the option(b) all the options follows the condition of system reliable.So the option(B) is False.
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when

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3 years ago
Read 2 more answers
It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.
Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way  merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

<em>For optimal 4-way merging, we need one dummy run with size 0.</em>

  1. Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300
  2. Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

       L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000

<em>The resulting run has length 6000 records</em>.

Part b

<u><em>For step 1</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec

So the input/output time is 46 seconds for step 01.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec

So the CPU  time is 23 seconds for step 01.

Total time in step 01

T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\

Total time in step 01 is 69 seconds.

<u><em>For step 2</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec

So the input/output time is 120 seconds for step 02.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec

So the CPU  time is 60 seconds for step 02.

Total time in step 02

T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\

Total time in step 02 is 180 seconds

Merging Time (Total)

<em>Now  the total time for merging is given as </em>

T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\

Total time in merging is 249 seconds seconds

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Here's something to stop you from getting repetitive when writing essays. Write a program that reads multiple lines of plain tex
Marianna [84]

Answer:

The output is attached below

Explanation:

d = {}

while True:

line = input("Enter line: ")

if len(line)==0:

break

token = line.split(' ')

for var in token:

try:

if len(var)==0:

continue

count = d[var]

d[var] = count + 1

except KeyError:

d[var] = 1

pass

for word in sorted(d):

print(word , d[word])

------------------

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3 years ago
Write a program that repeatedly shows the user a menu to select the shape form three main shapes or to print the shapes created
fomenos

Answer:

Explanation:

The following code is written in Python. It creates a program that keeps printing out a menu allowing the user to create shapes. These shapes are saved in an array called shapes. Once the user decides to exit, it prints all of the shapes in the array along with their total area. The output can be seen in the attached picture below. Due to technical difficulties, I have added the code as a txt file below.

3 0
2 years ago
fill in the balenkes ) 1)there are ................................... function keys on the keybord 2)pressing the end key moves
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Answer:

1.) There are 12 function keys 2.) The return Key

Explanation:

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