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3 years ago

9

20=10-2y+4+4y what does y equal

1 answer:

Mila [183]3 years ago

4 0

Answer:

y = 3

Step-by-step explanation:

$10-2y+4+4y+20$

Combine like terms

$2y+14=20$

Move all terms not containing y to the right side of the equation.

$2y=6$

Divide both sides by 2

y = 3

Plz mark me brainliest!

It's ok if u don't...lol

I hope this helped!!

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Factor the expression<br> 20g3 + 24g2 – 15g – 18

abruzzese [7]

First, put parenthesis around the first two numbers and the last two numbers.
(20g³+24g²) (-15g-18)
Then, take out the greatest common factor of both parenthesis.
4g²(5g+6)-3(5g+6)
You then separate the numbers outside the parenthesis and the numbers in the parenthesis.
(5g+6) (4g²-3)
Then you simplify the second set of numbers. Since the set of numbers can't be simplified, you would leave this problem as it is. I hope this makes sense.

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3 years ago

Answer this question

ElenaW [278]

Answer:

12−3xStep-by-step explanation:

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2 years ago

Please help me set up this problem, I’ll mark you brainiest if it’s correct <br> X/? = ?/?

drek231 [11]

Answer:

6.3 inches

Step-by-step explanation:

5/9 = 3.5/x

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3 years ago

Read 2 more answers

Plzzz help me with this I’ll give brainliest

scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-(-1)}{(-4)-(-4)}$

m= $\frac{7}{0}$

The slope is 90 degree

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-6}{(-4)-(-1)}$

m= $\frac{0}{(-3)}$

The slope is zero degree

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-4)-6}{2-2}$

m= $\frac{-10}{0}$

The slope is 90 degree

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-(-4)}{(-4)-(2)}$

m= $\frac{3}{-6}$

m= $\frac{-1}{2}$

The slope of the only line AB and CD are the same.

Thus, The quadrilateral ABCD is not a parallelogram

For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{2-3}{3-(-2)}$

m= $\frac{-1}{5}$

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-2}{2-3}$

m= $\frac{-3}{-1}$

m=3

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{0-(-1)}{(-3)-2}$

m= $\frac{-1}{5}$

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{3-0}{(-2)-(-3)}$

m=3

The slope of the line AB and CD are the same

The slope of the line BC and DA are the same

Thus, The quadrilateral ABCD is a parallelogram

3 0

3 years ago

Create a number line. Plot the following numbers on the number line: 5, -10, 20, -5, 0, 10, -20

Goryan [66]

-20,-10,-5,0,5,10,20

4 0

3 years ago