Correct question:
An elevator in a mine shaft is stopped at 25 feet below ground level. And then travels 28 feet downward. What equation can be written to find the final position in feet of the elevator in relations to ground level?
Answer:
-53 feets
Step-by-step explanation:
Initial stop point = 25 feets below ground level
Further distance traveled = 28 feets below ground level
Final position in feet = Initial stop point + further distance traveled
Note : distances or point traveled below ground level or downward is represented as negative.
Final position in feets = (-25)feets + (-28)feets
Final position in feets = - 53 feets
Ok, so:
For Part A, we have: P(Z|A)=P(Z and A)/P(A)
And if we replace, we got:
P(Z|A) = (0.15)/(0.25) and this is equal to 0.6.
For Part B, we have: P(A|Z)=P(Z and A)/P(Z)
P(A|Z) = (0.15)/(0.73) and this is equal to 0.205.
Answer:
2
Step-by-step explanation:
one+one=two
Answer:
Not a solution.
Step-by-step explanation:
(x, y)
(-1, 2)
Substitute the x and y values in the expression with the point given.
8x + y > -6
8(-1) + 2 > -6
-8 + 2 > -6
-6 > -6
Since our final value has to be greater than -6 but is instead equal to -6, the solution is not true.
Answer:the first one
Step-by-step explanation:
i am teacher lol
