What is the percentage of 377 of 325?

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

6 0

Answer: 116%

Hope this helps.

You might be interested in

Three differnt way to wright 3,705.692

Aleks [24]

Answer:

3,705.692

Three thousand seven hundred and five thoudand six hundred and ninety two thousandths.

3 thousands, 7 hundreds, 5 ones, 6 tenths, 9 hundredths, 2 thousandths

Step-by-step explanation:

Simple math.

6 0

3 years ago

assume that when adults with smartphones are randomly selected, 44% use them in meetings or classes. If 10 adult smartphones use

tensa zangetsu [6.8K]

Solution: The given random experiment follows Binomial distribution with $n=10,p=0.44$

Let $X$ be the number of adults who use their smartphones in meetings or classes.

Therefore, we have to find:

$P(X$

We know the binomial model is:

$P(X=x)=\binom{n}{x} p^{x} (1-p)^{n-x}$

$\therefore P(X$

$=\binom{10}{0}0.44^{0}(1-0.44)^{12-0}+\binom{10}{1}0.44^{1}(1-0.44)^{10-1}+\binom{10}{2}0.44^{2}(1-0.44)^{10-2}$

$=1 \times 1 \times 0.0030 + 10 \times 0.44 \times 0.0054 + 45 \times 0.1936 \times 0.009672$

$=0.0030+0.0238+0.0843$

$=0.1111$

Therefore, the probability that fewer than 3 of them is 0.1111

7 0

3 years ago

Calculate the average rate of change for the function

mezya [45]

$slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= 2(x-2)^2+1\qquad \begin{cases} x_1=-2\\ x_2=4 \end{cases}\implies \cfrac{f(4)-f(-2)}{4-(-2)} \\\\\\ \cfrac{[2(4-2)^2+1]~~ - ~~[2(-2-2)^2+1]}{4+2}\implies \cfrac{[9]~~ - ~~[33]}{6}\implies \cfrac{-24}{6}\implies -4$