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3 years ago

What is the percentage of 377 of 325?

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

6 0

Answer: 116%

Hope this helps.

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An architect is designing a building.each floor will be 12 feet tall.

Kamila [148]

Answer:

There are four students working on a project in math class. Miguel has completed 1/8 of the project, Gina has completed 13% of the project, Jatziry has completed 0.10 of the project, and Keva has completed 1/9 of the project. Make a list of the students in order from least to greatest by the amount of the project they have completed.

Step-by-step explanation:

I don't have points

3 0

2 years ago

A total of 30 percent of the geese included in a certain migration study were male. If some of the geese migrated during the stu

Serggg [28]

<h2>Answer:</h2>

(B). $\frac{7}{12}$

<h2>Step-by-step explanation:</h2>

In the question,

Let the total number of geese be = 100x

Number of Male geese = 30% = 30x

Number of Female Geese = 70x

Let us say 'kx' geese migrated from these geese.

Number of migrated Male geese = 20% of kx = kx/5

Number of migrated Female geese = 4kx/5

So,

Migration rate of Male geese is given by,

$\frac{(\frac{kx}{5})}{30x}$

Migration rate of Female geese is given by,

$\frac{(\frac{4kx}{5})}{70x}$

So,

The ratio of Migration rate of Male geese to that of Female geese is given by,

$\frac{\left[\frac{(\frac{kx}{5})}{30x}\right]}{\left[\frac{(\frac{4kx}{5})}{70x}\right]}=\frac{350}{4\times 150}=\frac{7}{12}$

Therefore, the ratio of the rate of migration of Male geese to that of Female geese is,

$\frac{7}{12}$

Hence, the correct option is (B).

6 0

3 years ago

Find the area of shaded region.

Rudiy27

Hey there mate ;),

Area of The shades region is 3098 m^2

The solution is attached as picture. Please check.

Answered by Benjemin

6 0

2 years ago

Options: for A-G

Sindrei [870]

Answer:

a. Definition of segment Bisector

b. Line segment KM

c. Given

d. Definition of segment bisector

e. Reflexive property of congruence

f. SAS

g. CPCTC (Corresponding parts of congruent triangles are congruent)

3 0

3 years ago

Two spherical shells have their mass uniformly distrubuted over the spherical surface. One of the shells has a diameter of 2 met

ivann1987 [24]

The moment of inertia of a spherical shell is I = mr²

If two spheres have the same moment of inertia, then
I₁ = I₂
m₁(r₁)² = m₂(r₂)²

Solve for the second mass:
m₂ = m₁ (r₁/r₂)²

Given m₁ = 1 kg, r₁ = 2 m, r₂ = 1m,
m₂ = (1 kg) (2 m / 1 m)² = 4 kg

7 0

3 years ago