Using a calculator, the slope of the line of best-fit is of 7.2.
<h3>How to find the equation of linear regression using a calculator?</h3>
To find the equation, we need to insert the points (x,y) in the calculator.
In this problem, the points are given as follows:
(-4,-32), (-2,-8), (0,10), (2,8), (4,32).
Using the calculator, the equation is:
y = 7.2x + 2.
Hence the slope is of 7.2.
More can be learned about a line of best-fit at brainly.com/question/22992800
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Find the area of all the separate figures and add them together
area of rectangle = length x width
11 x 3 = 33 ft
area of square = a^2
3^2 = 9ft
area of triangle = base x height over 2
11 x 3 = 33
33 over 2 = 16.5 ft
33 + 9 + 16.5 = 58.5 ft ^ 2
Since the length is 10 in. You must multiply it by
and then multiply by
. The reason for this is because if you divide ten by 5 it will be 2, then if you divide 2 by 2 it will be 1.
Hi there!
Answer:
<u><em>C.-8.4</em></u>
Step-by-step explanation:
divide by the numbers.
10.8-0.6=18.0=18
9.6-18
subtract the numbers.
9.6-18=-8.4
=-8.4
Hope this helps!
-Charlie
Have a great day!
Answer:
H0: μd=0 Ha: μd≠0
t= 0.07607
On the basis of this we conclude that the mean weight differs between the two balances.
Step-by-step explanation:
The null and alternative hypotheses as
H0: μd=0 Ha: μd≠0
Significance level is set at ∝= 0.05
The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571
The test statistic under H0 is
t = d/ sd/ √n
Which has t distribution with n-1 degrees of freedom
Specimen A B d = a - b d²
1 13.76 13.74 0.02 0.004
2 12.47 12.45 0.02 0.004
3 10.09 10.08 0.01 0.001
4 8.91 8.92 -0.01 0.001
5 13.57 13.54 0.03 0.009
<u>6 12.74 12.75 -0.01 0.001</u>
<u>∑ 0.06 0.0173</u>
d`= ∑d/n= 0.006/6= 0.001
sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882
sd= 0.05368
t= 0.001/ 0.05368/ √6
t= 0.18629/2.449
t= 0.07607
Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.
