Answer: 
Step-by-step explanation:
Given
Cost per student in the year 1978 is $2200
The cost increases to $10,300 in 2008
Suppose 
is the linear equation defining the cost per student after x years
Substitute the value for 1978
After 30 years it becomes
Thus, the linear equation becomes
Answer:
14
Step-by-step explanation:
(a+b)^2
(a+b)(a+b)
FOIL
a^2 + ab+ab + b^2
Combine like terms
a^2 +2ab + b^2
Rearranging
a^2+b^2 +2ab
We know a^2+b^2 = 4 and ab= 5
4 + 2(5)
4+10
14
x = 3 is the answer can you pls add me brainliest answer
Answer:
x=4
Step-by-step explanation:
6 - 6x = 5x – 9x - 2
6+2=5x-9x+6x
8=2x
4=x
What you need to do to be able to solve this is move all of the terms that have no variable and the ones that have the same variable to the other side. Once you have that, you should be able to do 6+2 and solve the side that has variables as if it has no variables. Remember that you have to flip the sign when you are moving all of the numbers. Then when you get to the step where both sides have only one number, that is when you would divide the other number, which in this case is 8, by 2, which is the number correlated with x. And that should get x by itself, and give you the solution.
