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Nat2105 [25]
3 years ago
14

URGENT!! please please help!!

Chemistry
1 answer:
Alex73 [517]3 years ago
8 0

Answer:

It may be too late, but you got lost in all that info. All they want is for you to show how many moles in 3.00 grams of Tin metal.

Explanation: I cannot print the dimensional analysis that is asked for, but we can do this.

Let’s use water instead of Tin, then you can figure it out. 1 mole of water is 2 H x 1 amu. 1 O at 16 amu. Forget the amu, just add the 16 + 2= 18 grams of Water In 1 mole. So 9 grams would be how many moles of water? 9 is 1/2 of 18 isn’t it? So it is 0.5 Moles.

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Metabolic activity in the human body releases approximately 1.0 x 104kJ of heat per day. Assuming the body is 50 kg of water, ho
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Answer:

The body temperature would rise by 47.85 °C

The  amount of water the body evaporates is  4.15 kg.

This makes sense because firstly the value obtained is positive  then secondly it is a normal occurrence in the real world that in a place where the temperature is high the body usually produce sweat in order to balance its internal temperature

Explanation:

Considering the relationship (between the heat released and the mass of the object)  as shown below

              q = msΔT    

where q is the heat released per day = 1.0 * 10^{4} kJ

              m is the mass of the body  = 50 kg

              ΔT  is the temperature rise = ?

               s is the specific heat  of water =  4,18kJ/kg^{o} C

              substituting values we have

                              1.0 * 10^{4} kJ  = (50kg) (4.18kJ/kg^{o}C ) ΔT

                              ΔT = \frac{1.0 * 10^{4}kg}{(50kg)(4.18kJ/kg^{o} C)}    

                                   =  47.85°C  

To maintain the normal  body temperature (98.6F = 37°C) the amount of heat released by metabolism activity must be utilized for evaporation of some amount of water

Hence

        Amount of water that must be evaporated =\frac{heat released per day}{heat of vaporization of water}

                                                                      = \frac{1.0* 10^{4}kJ}{2.41kJ/g} \\= 4149.38g\\=4.15kg  

          Note  (1 kg = 1000 g)

This makes sense because firstly the value obtained is positive  then secondly it is a normal occurrence in the real world that in a place where the temperature is high the body usually produce sweat in order to balance its internal temperature

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