i belive the answe is c and if im wrong im tarrably sorry
Answer:
Consider the followig calculation
Explanation:
a) use deal equation:
PV = nRT
ρ = m/V,= ==> V = m/ρ
therefore,
ρ = Pm/RT
convert 95 oF in degree
95 oF = 308.15 K
1 atm = 1.013 * 105 pascal
ρ = 1.013*105 * 29 * /8.314 * 308.15
= 1.146 kg/m3
b) again use ideal gas equation:
ρ = Pm/RT
T = 50 oF = 283.15 K
1 atm = 1.013 * 105 pascal
molar mass will be same
ρ = 1.013 * 105 * 29 / 8.314 * 283.15
ρ = 1.248 kg / m3
So,
c) . more than density of the hot, dry air computed in part (a)
The last 2. They both are correct. I hope this helps.
