Question

An aircraft is moving horizontally with a speed of 50m/s, at the height of 2km, an object is dropped from the aircraft. What is the vertical and horizontal velocity of an object if the angle is 23 degrees and the time interval for the object hits the ground?

Answer 1

Explanation:

use the diagram^

horizontal velocity of the object nvr changes, it'll stay 50m/s till it hits the ground

initial vertical velocity = 0

to find the final vertical velocity, use the formula:

$v {}^{2} = u {}^{2} + 2as$

where u = 0m/s, a = 9.8m/s², and s = 2000m

solve for v.

for time taken to reach ground, use the formula:

$v = u + at$

where v = the value for v u calculated above, u = 0 m/s, a = 9.8m/s² and solve for t.