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maxonik [38]
3 years ago
11

HELP: How do I graph this?

Mathematics
1 answer:
bonufazy [111]3 years ago
6 0

Answer:

Step-by-step explanation:

C against x

income against sale of x games

for the first equation, the gradient would be 8 and for the second one the gradient would r with a y intercept at 48000

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9x+18+3x=1
Katen [24]
The error is in the second step they subtracted 3 from both sides but it was a 3x, which you can not do.
Correction.
9x+18+3x=1
12x+18=1
12x=-17
x=-17/12
3 0
3 years ago
Read 2 more answers
The option for the first one is graph A or graph B
horrorfan [7]

First answer: Graph A

Second answer: E) Increase less

Graph A shows a flatter curve compared to B which is steeper. The steeper the curve, the faster the increase.

4 0
4 years ago
How many variable terms are in the expression 3x to the third power Y plus 5X to the second power plus Y +9
andrew-mc [135]

Well, variables are stuff like x and y because they can represent a number. They are variable in an equation. so if you have (3x^3)+(5X^2)+Y+9 then your variables are x X and Y (im assuming the capital X is there and not a typo) if that was a typo and meant to be lowercase, then its just a 2 variable with the x and y

8 0
3 years ago
Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.
Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is Q(x,y) is predicate that x then x^{2}. where x,y are rational numbers.

a)

when x=-2, y=1

Here -2 that is x  satisfied. Then

(-2)^{2}

4 this is wrong. since 4>1

That is x^{2}>y^{2} Thus Q(x,y) =Q(-2,1)is false.

b)

Assume Q(x,y)=Q(-5,2).

That is x=-5, y=2

Here -5 that is x this condition is satisfied.

Then

(-5)^{2}

25 this is not true. since 25>4.

This is similar to the truth value of part (a).

Since in both x satisfied and x^{2} >y^{2} for both the points.

c)

if Q(x,y)=Q(3,8) that is x=3 and y=8

Here 3 this satisfies the condition x.

Then 3^{2}

9 This also satisfies the condition x^{2}.

Hence Q(3,8) exists and it is true.

d)

Assume Q(x,y)=Q(9,10)

Here 9 satisfies the condition x

Then 9^{2}

81 satisfies the condition x^{2}.

Thus, Q(9,10) point exists and it is true. This satisfies the same values as in part (c)

6 0
3 years ago
11 is what percent of 300?
BabaBlast [244]

Answer: 11 is 3.667% of 300.

Step-by-step explanation: The 3.667% of 300 is 11.001, this is the closest possible to 11.

P.D. Hope this helps!

7 0
3 years ago
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