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MA_775_DIABLO [31]
3 years ago
13

Plz help me to answer

Mathematics
2 answers:
AVprozaik [17]3 years ago
4 0

Answer:

for 3, 4 or both?

4. is probably zero

Step-by-step explanation:

Wait is 4 a question?

Mrac [35]3 years ago
4 0

cos^2 x + \cos^2 y = \cos(2x + 2y)\\\\\implies \dfrac{d}{dx} (\cos^2 x + \cos^2 y) = \dfrac{d}{dx} \cos(2x+2y)\\\\\implies -2\cos x \sin x  -2 \cos y \sin y \dfrac{dy}{dx}=-\sin(2x+2y) \left(2+2\dfrac{dy}{dx} \right) \\\\\implies -2\cos x \sin x  -2 \cos y \sin y \dfrac{dy}{dx}=-2\sin(2x+2y) -2\sin(2x+2y)\dfrac{dy}{dx} \right) \\\\\implies 2 \sin(2x+2y) \dfrac{dy}{dx} - 2 \cos y \sin y \dfrac{dy}{dx} = 2 \cos x \sin x-2\sin(2x+2y)

\implies  \sin(2x+2y) \dfrac{dy}{dx} -  \cos y \sin y \dfrac{dy}{dx} =  \cos x \sin x-\sin(2x+2y)\\\\\implies  \dfrac{dy}{dx} [\sin(2x+2y) - \cos y \sin y] =  \cos x \sin x-\sin(2x+2y)\\\\\implies  \dfrac{dy}{dx} [\sin(2x+2y) - \cos y \sin y] =  \cos x \sin x-\sin(2x+2y)\\\\\implies \dfrac{dy}{dx} = \dfrac{\cos x \sin x-\sin(2x+2y)}{\sin(2x+2y) - \cos y \sin y}\\\\\implies y'(x) =  \dfrac{\cos x \sin x-\sin(2x+2y)}{\sin(2x+2y) - \cos y \sin y}

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Your 3 nieces and 3 nephews (6 children total) are visiting for the holidays. You must give them each a present. They all love l
marusya05 [52]

Answer:

The 6 Lego kits can be selected from the 9 available Lego kits in 84 ways.

Step-by-step explanation:

Use combinations to solve this problem.

Combination is defined as the selection of <em>r</em> elements from <em>n</em> distinct objects irrespective of the order. The objects cannot be replaced.

There are 9 Lego kits available.

And the total number of children is 6.

That is, we need to select 6 Lego kits from the 9 available Lego kits.

6 Lego kits can be selected from the 9 available Lego kits in 9\choose 6 ways.

Solving the combination as follows:

{9\choose 6}=\frac{9!}{6!\times(9-6)!} \\=\frac{362880}{720\times6}\\ =84

Thus, there are 84 ways to select 6 Lego kits from 9 available Lego kits.

4 0
3 years ago
5x-2y=2 slope intercept form?
Nata [24]

Answer:

y = \frac{5}{2}x-1  

Step-by-step explanation:

Slope-intercept form is represented by the formula y = mx  + b. So, to place the given equation in slope-intercept form, isolate the y on the left side and arrange the terms in that matching order. Remember, whatever you do to one side, do to the other:

5x-2y = 2\\-2y = -5x + 2\\\frac{-2}{-2}y = \frac{-5}{-2} x+\frac{2}{-2} \\y = \frac{5}{2} x-1

So, the slope-intercept form is y = \frac{5}{2}x-1.

6 0
3 years ago
What is the name of an investment in which deposits are made in fixed dollar amounts at regular intervals?
andrew11 [14]

Answer: periodic investment APEX

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Three dice are going to be rolled. What is the probability that the first die rolled is a 1, the second die rolled is a 2, and t
FromTheMoon [43]
Answer: The probability is 0.46%.

The chance of each given event happening is 1/6 because there are 6 different number on the dice and only 1 number is chose.

Therefore to find the combined probability, we have to multiply all the individual probabilities.

(1/6) x (1/6) x (1/6)

Or

(1/6)^3

The answer is about 0.46%,
3 0
3 years ago
What is the solution to -x2 + 5x - 3
CaHeK987 [17]

The solution to the equation is x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

Explanation:

Given that the equation is -x^2+5x-3=0

We need to determine the solution of the equation.

The solution of the equation can be determined using the quadratic formula.

The quadratic formula is given by

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Hence, from the equation, we have,

a=-1,\:b=5,\:c=-3

Substituting these values in the quadratic formula, we get,

x=\frac{-5\pm \sqrt{5^2-4\left(-1\right)\left(-3\right)}}{2\left(-1\right)}

Simplifying, we get,

x=\frac{-5\pm \sqrt{25-12}}{-2}

Simplifying the terms within the root, we get,

x=\frac{-5\pm \sqrt{13}}{-2}

Thus, the roots of the equation are x=\frac{-5+ \sqrt{13}}{-2} and x=\frac{-5- \sqrt{13}}{-2}

Taking out the negative sign, we get,

x=\frac{-(5- \sqrt{13})}{-2} and x=\frac{-(5+ \sqrt{13})}{-2}

Cancelling the negative sign, we get,

x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

Thus, the solutions of the equation are x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

7 0
3 years ago
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