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3 years ago

What is the difference in the graphs of f(x)=x^2 and f(-x)=(-x)^2?

Mathematics

1 answer:

drek231 [11]3 years ago

4 0

Answer:

B the graph is a refelction over the x axis

Step-by-step explanation:

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What is the value of the power?

Salsk061 [2.6K]

Answer:

Exponet of 2

Step-by-step explanation:

because i know trust me its right

3 0

4 years ago

20) Use the distributive property to factor the expression. 10xz − 20yz A) z(10x − 20y) B) 10(xz − 2yz) C) 10z(x − 2y) D) xyz(10

melisa1 [442]

Answer:

C. 10z(x - 2y)

Step-by-step explanation:

10xz − 20y

Factor the terms

Factors of 10xz = 2 × 5 × x × z

Factors of -20yz = (-1) × 2 × 2 × 5 × y × z

Identify their greatest common factor

The common factors are 2, 5, and z. The greatest common factor is 10z.

Rewrite them with the GCF as a factor

10xz = 10z × x

-20yz = 10z × (-2y)

Replace the terms in the original expression with the factored terms

10xz − 20yz = 10z(x) + 10z(-2y)

Use the distributive property to isolate the greatest common factor

10z(x) + 10z(-2y) = 10z(x - 2y)

4 0

3 years ago

Pllllllllllllllzzzzzzzzzzzzzzz hhheeeellllllllpppppppppppp

Scrat [10]

Answer:

I think it should be the third option

3 0

3 years ago

Simplify:3/4-1/3+1/12

goblinko [34]

Answer:

1/2

Step-by-step explanation:

5/12+1/12

=1/2

Here u goo hope it helps :))

4 0

3 years ago

Read 2 more answers

Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p

scZoUnD [109]

Answer:

The probability that they will teach different courses is $\frac{2}{3}$ .

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here x represents the course taught by the first part-time instructor and y represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events E is the ratio of the number of favorable outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

Compute the probability that they will teach different courses as follows:

$P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}$

Thus, the probability that they will teach different courses is $\frac{2}{3}$ .

3 0

3 years ago