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Aloiza [94]
3 years ago
7

The profit that the vendor makes per day by selling x pretzels is given by the function P(x) = -0.004 x^2 + 2.8x - 350. Find the

number of pretzels that must be sold to maximize profit A) 325 pretzels B) 340 pretzels C) 350 pretzels
Mathematics
1 answer:
Butoxors [25]3 years ago
4 0

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

P(x)=-0.004x^2+2.8x-350

So, we will first derivative it w.r.t to x, we get that

P'(x)=-0.008x+2.8

For critical points, we get that

P'(x)=0\\\\-0.008x+2.8=0\\\\-0.008x=-2.8\\\\x=\dfrac{2.8}{0.008}\\\\x=350

Now, we will check for maximum profit.

So, we will find Second derivation and then put the value of x = 350 in it.

p''(x)=-0.008

So, it will give maximum profit.

Hence, At 350 pretzels, there must be maximum profit.

Therefore, Option 'c' is correct.

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Show that each of these conditional statements is a tautology by using truth tables. a) [¬p ∧ (p ∨ q)] → q b) [(p → q) ∧ (q → r)
nlexa [21]

Step-by-step explanation:

To show that a statement is a tautology using truth table - is to show that all the entries in the expression are truths T.

We can do this by taking each statement, expression by expression. For example, to show that

[~p ∧ (p ∨ q)] → q

is a tautology, knowing we have 3 columns, we have 2^3 = 8 rows. We start by putting putting truth values for p, q, and r respectively

Next, we find ~p, then find (p ∨ q), then find ~p ∧ (p ∨ q), before finally arriving at the required [~p ∧ (p ∨ q)] → q

TERMINOLOGIES AND SYMBOLS

- T means Truth

- F means False

- ~p means negation of p.

~p is F if p is T, and vice versa

- ∧ means conjunction.

p ∧ q is T only if p is T and q is T.

- ∨ means disjunction.

p ∨ q is T if either p or q is T.

- → is for conditional 'if then'

p → q is T if both p and q are T, or both p and q are F, or p is F and q is T, otherwise, it is F.

THE STEP BY STEP WORKINGS FOR THE STATEMENTS GIVEN ARE IN THE ATTACHMENT.

8 0
3 years ago
Read 2 more answers
Among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a ma
scoundrel [369]

Answer:

Step-by-step explanation:

Given that among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a mathematics course, and 123 are enrolled in both an economics and a mathematics course.

From the above we find that

a) either economics of Math course is

315+213-123 =405

Out of 500 students 405 have taken either Math or Economics

Hence

c) student who have taken neither = 500-405 =95

Exactly one course is either math or economics - both

= 405-123 = 282

3 0
4 years ago
I need the answer to the below question
kiruha [24]
Send your snap I can help
3 0
3 years ago
Arbara signed up for dance lessons at Dance Unlimited. She was charged $55 per month for lessons and a one-time recital fee of $
kramer

Given:

Per month fee = $55

One-time recital fee = $165

The equation represents the $495 total cost that Barbara paid to Dance Unlimited.

495=165+55m

To find:

We need to find the number of month Barbara receive dance lessons from Dance Unlimited.

Solution:

We have,

495=165+55m

Here, m is number of months. We need to isolate m.

Subtract 165 from both sides.

495-165=55m

330=55m

Divide both sides by 55.

\dfrac{330}{55}=m

6=m

The value of m is 6. So, the required number of month Barbara receive dance lessons from Dance Unlimited is 6.

8 0
4 years ago
Please help me answer this
irga5000 [103]
I think it is -0.125.
It might also be 0.125
4 0
3 years ago
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