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shepuryov [24]
3 years ago
5

Given the rate equation, when the concentration of A is doubled while that of B is halved, the rate will Given the rate equation

, when the concentration of A is doubled while that of B is halved, the rate will blank the original rate. the original rate.
Chemistry
1 answer:
melisa1 [442]3 years ago
6 0

Answer:

I believe the question is incomplete as the rate equation was not included in the question, but no need to be worried I can be of help. Here is the complete question:

Given: A + 3B  2C + D

This reaction is first order with respect to reactant A and second order with respect to reactant B. If the concentration of A is doubled and the concentration of B is halved, the rate of the reaction would _____ by a factor of _____.

(a) increase, 2

(b) decrease, 2

(c) increase, 4

(d) decrease, 4

(e) not change

Explanation:

Solving the above question, the rate of the reaction will decrease and by factor of 2. How?

K1 = [A] [B]^2 i.e, reactant A is first order, reactant B is second order.

k2 = 2[A] [B/2]^2 that is, concentration of reactant A is doubled, concentration of reactant B is halved.

Comparing both rate of reactions:

k1/k2 = [A] [B/2] / 2[A] [B/2]^2

k1/k2 = 4 [A] [B]^2 /2 [A] [B]^2

k1 /k2 = 4 [B]^2 / 2[B]^2

k1/k2 = 2

The rate of the reaction is therefore decreased and by 2.

With this ideas of how to solve this kind of question, you can use it to solve for the actual question if the question is solved is not the actual one.

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Annual precipitation rates can be collected for several years added together and divided by the number of years to obtain an ave
larisa [96]

Answer:

true

Explanation:

3 0
3 years ago
A compound containing Na, C, and O is found to have 1.06 mol Na, 0.528 mol C, and 1.59 mol O. What is the empirical formula of t
Effectus [21]

Given :

Moles of Na : 1.06

Moles of C : 0.528

Moles of O : 1.59

To Find :

The empirical formula of the compound.

Solution :

Dividing moles of each atom with the smallest one i.e 0.528 .

So,

Na : 1.06/0.528 = 2.007 ≈ 2

C : 0.528/0.528 = 1

O : 1.59/0.528 = 3.011 ≈ 3

Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.

So, empirical formula is Na_2CO_3 .

Hence, this is the required solution.

5 0
2 years ago
"Write the electron Configuration expected for element 113 and the configurations for the two cations it is most likely to form"
arlik [135]

Answer:

Element:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d¹⁰7p¹

Cations:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d¹⁰

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶5f¹⁴6d¹⁰

Explanation:

The electron configuration is the distribution of the electrons in the sublevels in order of the crescent energy of them. The crescent energy of the sublevels follows the Linus Pauling's diagram, which is attached below. The sublevel "s" comports until 2 electrons, the sublevel "p" until 6 electrons, the sublevel "d" until 10 electrons, and sublevel "f" until 14 electrons.

So, for the element with an atomic number of 113, the neutral atom will have 113 electrons:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d¹⁰7p¹

Thus the element is at the 7 period (the highest level), and group 13 (most energic sublevel p with 1 electron), the group of the aluminum. It needs to lose 3 electrons to be stable and follow the octet rule, but the subshells of the last shell are too far away in energetic order, thus, it most probably to lose the electron of 7p and form a monovalent cation, and can lose the two electrons of 7s to form a trivalent cation:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d¹⁰

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶5f¹⁴6d¹⁰

5 0
3 years ago
When describing velocity what should be included?
Andrei [34K]
Direction and speed. Hope it helps
7 0
3 years ago
Read 2 more answers
The calvin cycle and the krebs are referred to as cycles of chemical reactions because they
Schach [20]

Answer:

The options are

a. occur inside organelles. b. start over continually. c. are part of the carbon cycle. d. allow energy to flow in ecosystems.

The answer is b. Start over continually

Explanation:

The two cycles involves a continuous process as long as the reactants are present under suitable conditions. The cycle happens all the time due to it being necessary to produce important products all the time for the body system.

A good example involves the existing Carbon dioxide and water reacting together to get converted into substance that could provide energy (ATP and NADH) such as Glucose.

8 0
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