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shepuryov [24]
3 years ago
5

Given the rate equation, when the concentration of A is doubled while that of B is halved, the rate will Given the rate equation

, when the concentration of A is doubled while that of B is halved, the rate will blank the original rate. the original rate.
Chemistry
1 answer:
melisa1 [442]3 years ago
6 0

Answer:

I believe the question is incomplete as the rate equation was not included in the question, but no need to be worried I can be of help. Here is the complete question:

Given: A + 3B  2C + D

This reaction is first order with respect to reactant A and second order with respect to reactant B. If the concentration of A is doubled and the concentration of B is halved, the rate of the reaction would _____ by a factor of _____.

(a) increase, 2

(b) decrease, 2

(c) increase, 4

(d) decrease, 4

(e) not change

Explanation:

Solving the above question, the rate of the reaction will decrease and by factor of 2. How?

K1 = [A] [B]^2 i.e, reactant A is first order, reactant B is second order.

k2 = 2[A] [B/2]^2 that is, concentration of reactant A is doubled, concentration of reactant B is halved.

Comparing both rate of reactions:

k1/k2 = [A] [B/2] / 2[A] [B/2]^2

k1/k2 = 4 [A] [B]^2 /2 [A] [B]^2

k1 /k2 = 4 [B]^2 / 2[B]^2

k1/k2 = 2

The rate of the reaction is therefore decreased and by 2.

With this ideas of how to solve this kind of question, you can use it to solve for the actual question if the question is solved is not the actual one.

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Students in a chemistry class added 5 g of Zinc to 50 g of hydrochloric acid. A chemical reaction occurred that produced zinc ch
Vinil7 [7]

Answer:

Mass = 11 g

Explanation:

Given data:

Mass of Zn = 5 g

Mass of HCl = 50 g

Mass of hydrogen gas produced = 6 g

Mass of zinc chloride produced = ?

Solution:

Chemical equation:

Zn + 2HCl    →   ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 5 g / 65.38 g/mol

Number of moles = 0.08 mol

Number of moles of HCl :

Number of moles = mass / molar mass

Number of moles = 50 g / 36.5 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of both reactant with zinc chloride.

              Zn           :           ZnCl₂

               1             :             1

              0.08       :        0.08

            HCl          :         ZnCl₂

              2            :           1

             1.4          :         1/2×1.4 =0.7 mol

The number of moles of zinc chloride produced by Zn are less so it will limiting reactant.

Mass of zinc chloride:

Mass = number of moles × molar mass

Mass = 0.08 mol × 136.3 g/mol

Mass = 11 g

5 0
3 years ago
Calculate the molarity of each of the following solutions. Use the periodic table if necessary. A salt solution with a volume of
Andru [333]

The molarity of the NaCl in the 250 ml slat solution is 2.8M.

<h3>What is molarity?</h3>

The molarity of a solution is defined as the concentration of a solute per unit volume of the solution.

Given, the volume of the solution is 250 ml converted into l 0.25

The number of moles of NaCl is 0.70.

By the formula  of molarity

M = \dfrac{n}{V}\\\\\\M = \dfrac{0.70}{0.25} = 2.8 M

Thus, the molarity is 2.8 M.

Learn more about molarity

brainly.com/question/14693949

7 0
2 years ago
What is the mole fraction, X, of solute and the molality, m (or b), for an aqueous solution that is 15.0% NaOH by mass?
GalinKa [24]
Hello!

a) The mole fraction of solute of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams of water. We can calculate the number of moles of each one in the following way:

molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH \\ \\ moles H_2O=85 gH_2O* \frac{1 mol H_2O}{18 g H_2O}=4,7222 moles H_2O

To finish, we calculate the mole fraction by dividing the moles of NaOH between the total moles:

X_{NaOH}= \frac{moles NaOH}{total moles}= \frac{0,3750 moles NaOH}{0,3750 moles NaOH+4,7222 molesH_2O} =0,073

So, the mole fraction of NaOH is 0,073

b) The molality (moles NaOH/ kg of solvent) of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams (0,085 kg) of water. We can calculate the moles of NaOH in the following way:

molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH

Now, we apply the definition of molality to calculate the molality of the solution:

mNaOH= \frac{moles NaOH}{kg_{solvent}}=  \frac{0,3750 moles NaOH}{0,085 kg H_2O}=4,41 m

So, the molality of this solution is 4,41 m

Have a nice day!
4 0
3 years ago
You need to heat a solid to a temperature of 250 Celsius. What would be the most appropriate type of glassware to use?
Andrei [34K]
<span>A crucible and cover </span>
3 0
3 years ago
What is the volume of 10 paper clips in ml
vredina [299]

Answer:

10.000

Explanation:

7 0
3 years ago
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