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ivann1987 [24]
2 years ago
12

Calculate the molarity of each of the following solutions. Use the periodic table if necessary. A salt solution with a volume of

250 mL that contains 0. 70 mol NaCl. M.
Chemistry
1 answer:
Andru [333]2 years ago
7 0

The molarity of the NaCl in the 250 ml slat solution is 2.8M.

<h3>What is molarity?</h3>

The molarity of a solution is defined as the concentration of a solute per unit volume of the solution.

Given, the volume of the solution is 250 ml converted into l 0.25

The number of moles of NaCl is 0.70.

By the formula  of molarity

M = \dfrac{n}{V}\\\\\\M = \dfrac{0.70}{0.25} = 2.8 M

Thus, the molarity is 2.8 M.

Learn more about molarity

brainly.com/question/14693949

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The solubility of oxygen in lakes high in the Rocky Mountains is affected by the altitude. If the solubility of O2 from the air
IceJOKER [234]

Answer:

1.75\cdot 10^{-4} M

Explanation:

Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:

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Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.

Given initially:

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Also, at sea level, we have an atmospheric pressure of:

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Given mole fraction:

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According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:

p^o = \chi_{O_2} p

Then the equation becomes:

S_1 = k_H \chi_{O_2} p

Solve for k_H:

k_H = \frac{S_1}{\chi_{O_2} p} = \frac{2.67\cdot 10^{-4} M}{0.209\cdot 1.00 atm} = 0.001278 M/atm

Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:

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Apply Henry's law using the constant we found:

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8 0
3 years ago
Hydrogen reacts with chlorine to form hydrogen chloride (HCl (g), mc012-1.jpgHf = –92.3 kJ/mol) according to the reaction below.
Kobotan [32]

<u>Given:</u>

H2(g) + Cl2 (g) → 2HCl (g)

<u>To determine:</u>

The enthalpy of the reaction and whether it is endo or exothermic

<u>Explanation:</u>

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<u>Ans:</u> The enthalpy of reaction is -184. kJ and the reaction is exothermic

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