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3 years ago

Which of these questions is a scientific question?

Chemistry

1 answer:

n200080 [17]3 years ago

5 0

A or B but i'm leaning more towards A

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QUESTION 1 (POLL)

Airida [17]

Answer:

They stay the same

Explanation:

4 0

3 years ago

In general, both cations and anions will __________ as you go down a group.

madam [21]

A because cation is positive and anion is negative evening it out at constant.

8 0

2 years ago

Describe the photoelectric effect and explain why it made modifications to the Rutherford model necessary.

Furkat [3]

Photoelectric effect refer to the emission of electron or free carriers when light shine into a material. According to the Rutherford model, light of any energy should be able to make electrons leave the atom and be emitted. The energy of the emitted electrons should be related to the intensity of the light. But the energy of the electron is actually only related to the energy of the light

6 0

3 years ago

Read 2 more answers

Which statement concerning how geologists locate an earthquake's epicenter are accurate? check all that apply

allochka39001 [22]

Answer:

D.Geologists use data from three or more data stations to determine the location of the epicenter.

6 0

2 years ago

Read 2 more answers

Antimony has two naturally occuring isotopes, 121 Sb and 123 Sb . 121 Sb has an atomic mass of 120.9038 u , and 123 Sb has an at

valina [46]

Answer:

Percentage abundance of 121 Sb is = 57.2 %

Percentage abundance of 123 Sb is = 42.8 %

Explanation:

The formula for the calculation of the average atomic mass is:

$Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})$

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 121 Sb :

% = x %

Mass = 120.9038 u

For second isotope, 123 Sb:

% = 100 - x

Mass = 122.9042 u

Given, Average Mass = 121.7601 u

Thus,

$121.7601=\frac{x}{100}\times 120.9038+\frac{100-x}{100}\times 122.9042$

$120.9038x+122.9042\left(100-x\right)=12176.01$

Solving for x, we get that:

x = 57.2 %

Thus, percentage abundance of 121 Sb is = 57.2 %

percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %

6 0

3 years ago