Elements which have high electronegativities occur in Group: IA IIA VIIA O

GaryK [48]

Liquids have more kinetic energy in their particles compared to solids. this allows the particles to move more freely, hence why they are fluids

Liquids diffuse from a region of high concentration to a region of low concentration, until equilibrium is reached

When heat is applied the particles gain more kinetic energy so they now have enough energy to overcome the bonds holding them in the liquid. this means they can evaporate off

8 0

3 years ago

Calculate the number of moles of an ideal gas if it occupies 1750 dm3 under 125,000 Pa at a temperature of 127 C.

Phoenix [80]

Hey there!

* Converts 1750 dm³ in liters :

1 dm³ = 1 L so 1750 dm³ = 1750 liters

* Convertes 125,000 Pa in atm :

1 Pa = 9.86*10⁻⁶ atm so 9.86*10⁻⁶ / 125,000 => 1.233 atm

* Convertes 127ºC in K :

127 + 273.15 => 400.15 K

R = 0.082 atm.L/mol.K

Finally, it uses an equation of clapeyron :

p * V = n * R * T

1.233 * 1750 = n * 0.082 * 400.15

2157.75 = n * 32.8123

n = 2157.75 / 32.8123

n = 65.76 moles

hope this helps!

5 0

3 years ago

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During the titration of a diluted vinegar sample with a sodium hydroxide solution, the volume of sodium hydroxide used was less

lapo4ka [179]

Answer:

B and D could be true

Explanation:

A volume of sodium hydroxide less than expected could occurs for two reasons:

The real concentration of sodium hydroxide was higher than expected or the amount of vinegar added was less than expected:

A. The sodium hydroxide solution had been allowed to stand exposed to the air for a long time prior to the titration. FALSE. A long expose to the air decreases concentration of the NaOH.

B. The volumetric flask used to prepare the diluted vinegar solution was rinsed with water prior to use. TRUE. You add a less amount of vinegar doing you require less amount of NaOH than expected.

C. The burette used to deliver the sodium hydroxide solution was rinsed with water prior to use. FALSE. Thus, you add a less amount of NaOH than expected. To explain the matter, you add more NaOH than expected.

D. The pipette used to deliver the vinegar solution was rinsed with water prior to use. TRUE. Again, you are adding a less amount of Vinegar than expected doing the necessary NaOH during titration less than expected

6 0

3 years ago

A 1.2516 gram sample of a mixture of caco3 and na2so4 was analyzed by dissolving the sample and completely precipitating the ca

Dennis_Churaev [7]

Answer:

0.009725 moles of H2C2O4

0.009725 moles CaCO3

Mass percentage = 77.77%

Explanation:

Step 1: The balanced equation

2MnO4- +5C2H2O4+6H+ →2Mn2+ +10CO2+8H2O

We can see that for 2 moles of Mno4- consumed , there is 5 moles of C2H2O4 needed and 6 moles H+ to produce 2 moles Mn2+, 10 moles of CO2 and 8 moles of H2O

Step 2: Calculate moles of MnO4-

Molarity = Moles/volume

Moles of Mno4- = Molarity of MnO4- * Volume of Mno4-

Moles of Mno4- = 0.1092M * 35.62 *10^-3 L

Moles of MnO4- = 0.00389 moles

Step 3: Calculate moles of H2C2O4

Since there is needed 5 moles of C2H2O4 to consume 2 moles of MnO4-

then for 0.00389 moles of MnO4-, there is 5/2 *0.00389 = 0.009725 moles of H2C2O4

Step 4: Calculate moles of CaCO3

moles of H2C2O4 = moles CaCO3, therefore, 0.009725 moles H2C2O4 = 0.009725 moles CaCO3

Step 5: Calculate mass of CaCO3

Molar mass of CaCO3 = 100.09 g/mole

Mass of CaCO3 = moles of CaCO3 * Molar mass of CaCO3

Mass of CaCO3 = 0.009725 moles * 100.09 g/mole = 0.9734 g

Step 6: Calculate percentage by weight of CaCO3

Mass of CaCO3 = 0.9734g

Mass of original sample = 1.2516g

Mass percentage = 0.9734/1.2516 *100% = 77.77%

6 0

3 years ago

Which one is you fav one

serious [3.7K]

Answer:

the 3rd one

Explanation:

8 0

3 years ago

Read 2 more answers

Elements which have high electronegativities occur in Group: IA IIA VIIA O​

Elements which have high electronegativities occur in Group: IA IIA VIIA O