I'm not sure what your table and graph look like but they might both represent the relationship between numbers, like the common difference (+5 ect) They could also both represent positive growth or negative growth depending on how the graph and table look.
Hope this helps!
Step-by-step explanation:
I am not sure what your problem here is.
you understand the inequality signs ?
anyway, to get
6×f(-2) + 3×g(1)
we can calculate every part of the expression separately, and then combine all the results into one final result.
f(-2)
we look at the definition.
into what category is -2 falling ? the one with x<-2, or the one with x>=-2 ?
is -2 < -2 ? no.
is -2 >= -2 ? yes, because -2 = -2. therefore, it is also >= -2.
so, we have to use
1/3 x³
for x = -2 that is
1/3 × (-2)³ = 1/3 × -8 = -8/3
g(1)
again, we look at the definition.
into what category is 1 falling ? the one with x > 2 ? or the one with x <= 1 ?
is 1 > 2 ? no.
is 1 <= 1 ? yes, because 1=1. therefore it is also <= 1.
so we have to use
2×|x - 1| + 3
for x = 1 we get
2×0 + 3 = 3
6×f(-2) = 6 × -8/3 = 2× -8 = -16
3×g(1) = 3× 3 = 9
and so in total we get
6×f(-2) + 3×g(1) = -16 + 9 = -7
If the 1m turns into 3m then he cm increases also by 3.The 3 meters would equal 300 cm.
Step-by-step explanation:
Take the number as x
12x-40=7x+25
collect like terms
12x-7x=25+40
5x=65(divide both sides by 5)
x=13
Therefore number is 13
Answer:
4951 students
Step-by-step explanation:
If there was 99 students from each state, that would make the total to be:
99 * 50 = 4950
We can use the pigeon hole principle to make this the minimum number required.
The pigeon hole principle basically tells us that if you have more "pigeons" than "holes" then there must be one hole with multiple objects in it.
So, using this idea, we see that:
we need at least 1 more to ensure this
So, min number required would be
4950 + 1 = 4951
