Question

A rectangle pool has an area of 880 square feet. the length is 10 feet longer than the width. Find the dimensions of the pool

Answer 1

A=LW, and we are told that L=W+10

Using L=W+10 in A=LW you have:

A=(W+10)W

A=W^2+10W

W^2+10W=880, we are told that A=880 so

W^2+10W=880  now we can complete the square...

W^2+10W+25=905

(W+5)^2=905

W+5=±√905

W=-5±√905, since W>0

W=-5+√905  and since L=W+10

L=5+√905

W=-5+√905 ft and L=5+√905 ft

If we want an approximation:

W≈25.08 ft and L≈35.08 ft  (both dimensions to the nearest hundredth)