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bulgar [2K]
4 years ago
14

A rectangle pool has an area of 880 square feet. the length is 10 feet longer than the width. Find the dimensions of the pool

Mathematics
1 answer:
ddd [48]4 years ago
3 0
A=LW, and we are told that L=W+10

Using L=W+10 in A=LW you have:

A=(W+10)W

A=W^2+10W

W^2+10W=880, we are told that A=880 so

W^2+10W=880  now we can complete the square...

W^2+10W+25=905

(W+5)^2=905

W+5=±√905

W=-5±√905, since W>0

W=-5+√905  and since L=W+10

L=5+√905

W=-5+√905 ft and L=5+√905 ft

If we want an approximation:

W≈25.08 ft and L≈35.08 ft  (both dimensions to the nearest hundredth)
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Twelve subtracted from twelve times a number is 240. What is the number?
vovangra [49]

Answer:

21

Step-by-step explanation:

Let x = the number

12x-12 = 240

12x = 252

x = 21

5 0
3 years ago
What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

1 > (x - 2)/3

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0
3 years ago
3/5 + 3/7 = it a Fraction problem
Rudik [331]
<span>3/5 + 3/7 
Multiply the denominator until they have the same common denominator.
21/35 + 15/35
Add the numerators but NOT the denominators
Final Answer: 36/35 or 1 1/35</span>
5 0
3 years ago
Read 2 more answers
The legs of a right triangle are 10 cm and 24 cm. What is the length of the hypotenuse?
n200080 [17]
To determine the length of the hypotenuse, apply Pythagorean theorem.

A^2 + B^2 = C^2
(10)^2 + (24)^2 = C^2
100 + 576 = C^2
676 = C^2
C = 26 cm.

The hypotenuse is 26 cm.
6 0
4 years ago
Read 2 more answers
NEED HELP PLEASE!!!! (10 PTS)
slavikrds [6]
Tigers:-

f(t)  = 7(1 + 0.1)^2   where t = number of years

Eagle 

g(t)  =  15 + 2t


B  after ten year  number tigers = f(t) = 7(1 + 0.1)^10  =   18

  number of eagles = 15 + 10(2) = 35

C when the number of tigers = number eagles the 2 functions will be equal;-

f(t) = g(t)  that is:-

7* 1.1^t  = 15 + 2t

solve for t
5 0
3 years ago
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